A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from supplier A. The probability is (Type an integer or decimal rounded to four decimal places as needed.)
A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from supplier A. The probability is (Type an integer or decimal rounded to four decimal places as needed.)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A
arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from
supplier A.
The probability is
(Type an integer or decimal rounded to four decimal places as needed.)
Expert Solution

Step 1
Answer:- Given, A building contractor buys 70% of his cement from supplier A and 30% from supplier B.
That is , P( supplier A) = 70% = 0.70
P( supplier B) = 30% = 0.30
Aslo given , A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged.
That is, P(undamaged from A) = 75% = 0.75
P(undamaged from B) = 80% = 0.80
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