A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from supplier A. The probability is (Type an integer or decimal rounded to four decimal places as needed.)
A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from supplier A. The probability is (Type an integer or decimal rounded to four decimal places as needed.)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A
arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from
supplier A.
The probability is
(Type an integer or decimal rounded to four decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F940311b9-5876-4193-b2f2-017f83b935f7%2F0d453472-6521-4850-9946-36b5d60a6101%2Fwrnwwcd_processed.png&w=3840&q=75)
Transcribed Image Text:A building contractor buys 70% of his cement from supplier A and 30% from supplier B. A total of 75% of the bags from A
arrive undamaged, while 80% of the bags from B arrive undamaged. Find the probability that an undamaged bag is from
supplier A.
The probability is
(Type an integer or decimal rounded to four decimal places as needed.)
Expert Solution
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Step 1
Answer:- Given, A building contractor buys 70% of his cement from supplier A and 30% from supplier B.
That is , P( supplier A) = 70% = 0.70
P( supplier B) = 30% = 0.30
Aslo given , A total of 75% of the bags from A arrive undamaged, while 80% of the bags from B arrive undamaged.
That is, P(undamaged from A) = 75% = 0.75
P(undamaged from B) = 80% = 0.80
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