A builder calculated an approximate99.7% confidence interval for thepopulation mean price for houses,based on the following sample data:From a sample of 1600 houses, thesample mean price is $300,000.Assume the population standarddeviation is $11,726. What is theconfidence interval? Assume thedistribution of home prices is normallydistributed. Enter your answer in theformat (lower,upper) where "lower" isthe lower confidence limit and "upper"is the upper confidence limit. Roundeach numerical input to the nearestinteger. Do not include the dollarsign(s) in your answer.

The 99.7% confidence interval for the population mean prices for houses is obtained below as…

Answered: A builder calculated an approximate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What percentage of hospitals provide at least some charity care? Based on a random sample of 10 hospital reports from eastern states, the sample mean was x = 62.3 % and the sample standard deviation was s = 8.0 %. a. Find a 98% confidence interval for the population average µ of the percentage of hospitals providing at least some charity care. b. Interpretation. What does the confidence interval mean in the context of this problem?
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
From the data plot provided please answer the following questions.
In a random sample of 60 refrigerators, the mean repair cost was $111.00 and the population standard deviation is $16.40. Construct a 95% confidence interval for the population mean repair cost. Interpret the results. Construct a 95% confidence interval for the population mean repair cost. The 95% confidence interval is ( D. (Round to two decimal places as needed.)
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The distribution of study times for first-year students follow a Normal distribution with a standard deviation σ = 48 minutes. Suppose a sample of 344 students found that the mean study time for these students was x¯= 170 minutes per week. Use this to find a 94.38% confidence interval to estimate the mean study time for all students. We are 94.38% confident that the mean study time for first-year students is between the following ( answer) minutes and ( answer) minutes. The answer needs to be the mean study time for first-year students is between what amount of minutes and the following minutes.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 65 dates, the mean record high daily temperature in a certain city has a mean of 84.70°F. Assume the population standard deviation is 14.54°F.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals From a random sample of 43 business days, the mean closing price of a certain stock was $107.58. Assume the population standard deviation is $10.01. The 90% confidence interval is ( ). (Round to two decimal places as needed.)
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In order to estimate the average amount a customer spends on a meal in a major restaurant, data was collected from a sample of 30 customers. Suppose the population standard deviation is $3 . If the sample mean is $22, what is the 95% confidence interval for the population mean? Select one: a. [20.93 , 23.07] b. [20.59 , 23.41] c. [21.99 , 22.01] d. [20.95 , 23.05]
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 31 business days, the mean closing price of a certain stock was $110.20. Assume the population standard deviation is $11.44. The 90% confidence interval is (). (Round to two decimal places as needed.) ...
a researcher wishes to develop an interval estimate for response scores on user surveys. She's not sure about the standard deviation, but in previous years the scores have ranged from 25 to 86. How large a sample should she draw if she wants to construct a 95% confidence interval level that will be within 3 points of the population mean score?

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