A brass specimen of the circular cross-section is fractured at 151 kN force and the final length of the specimen at fracture is 49 mm. The fracture strength of the specimen is found to be 74 kN/mm2. The percentage of elongation of the specimen is 42 %. Determine the following (i) Diameter of the specimen ii) Initial length of the specimen iii) Stress under an elastic load of 16 kN iv) Young's Modulus if the elongation is 1.6 mm at 16 kN (v) Final diameter if the percentage of reduction in area is 20 % solve: Stress under the elastic load (in N/mm2) = Young's Modulus of the Specimen (in N/mm2) = Final Area of the Specimen at Fracture (in mm) =
A brass specimen of the circular cross-section is fractured at 151 kN force and the final length of the specimen at fracture is 49 mm. The fracture strength of the specimen is found to be 74 kN/mm2. The percentage of elongation of the specimen is 42 %. Determine the following (i) Diameter of the specimen ii) Initial length of the specimen iii) Stress under an elastic load of 16 kN iv) Young's Modulus if the elongation is 1.6 mm at 16 kN (v) Final diameter if the percentage of reduction in area is 20 % solve: Stress under the elastic load (in N/mm2) = Young's Modulus of the Specimen (in N/mm2) = Final Area of the Specimen at Fracture (in mm) =
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A brass specimen of the circular cross-section is fractured at 151 kN force and the final length of the specimen at fracture is 49 mm. The fracture strength of the specimen is found to be 74 kN/mm2. The percentage of elongation of the specimen is 42 %.
Determine the following
(i) Diameter of the specimen
ii) Initial length of the specimen
iii) Stress under an elastic load of 16 kN
iv) Young's Modulus if the elongation is 1.6 mm at 16 kN
(v) Final diameter if the percentage of reduction in area is 20 %
solve:
Stress under the elastic load (in N/mm2) =
Young's Modulus of the Specimen (in N/mm2) =
Final Area of the Specimen at Fracture (in mm) =
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