A brass cylinder has a cross-sectional area of 482 cm² at -5 °C. Find its change in area when heated to 95 °C. The coefficient of thermal expansion for brass is 1.9 x 10-5/°C.

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement:

A brass cylinder has a cross-sectional area of 482 cm² at -5 °C. Find its change in area when heated to 95 °C. The coefficient of thermal expansion for brass is 1.9 x 10⁻⁵ /°C.

### Explanation:

This problem requires the application of the formula for the change in area due to thermal expansion. The change in area \( \Delta A \) can be calculated using the formula:

\[ 
\Delta A = A_0 \cdot \beta \cdot \Delta T 
\]

where:
- \( A_0 \) is the initial area (482 cm²).
- \( \beta \) is the coefficient of linear expansion, given as \( 1.9 \times 10^{-5} \, \text{°C}^{-1} \). Note that for area expansion, you need to use twice the linear expansion coefficient.
- \( \Delta T \) is the change in temperature (95 °C - (-5) °C = 100 °C).

By substituting the values into the formula, the change in area can be calculated.
Transcribed Image Text:### Problem Statement: A brass cylinder has a cross-sectional area of 482 cm² at -5 °C. Find its change in area when heated to 95 °C. The coefficient of thermal expansion for brass is 1.9 x 10⁻⁵ /°C. ### Explanation: This problem requires the application of the formula for the change in area due to thermal expansion. The change in area \( \Delta A \) can be calculated using the formula: \[ \Delta A = A_0 \cdot \beta \cdot \Delta T \] where: - \( A_0 \) is the initial area (482 cm²). - \( \beta \) is the coefficient of linear expansion, given as \( 1.9 \times 10^{-5} \, \text{°C}^{-1} \). Note that for area expansion, you need to use twice the linear expansion coefficient. - \( \Delta T \) is the change in temperature (95 °C - (-5) °C = 100 °C). By substituting the values into the formula, the change in area can be calculated.
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