A box with a square base and open top must have a volume of 78732 cm, We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only æ, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of r.] Simplify your formula as much as possible. A(z) = Next, find the derivative, A'(x). A' (x) = %3! Now, calculate when the derivative equals zero, that is, when A (z) 0. [Hint: multiply both sides by .) %3D A'(x) = 0 when = %3D We next have to make sure that this value of x gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = %3D Evaluate A"(x) at the r-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(x) is concave up around that value, so the zero of A'(x) must indicate a local minimum for A(). (Your boss is happy now.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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A box with a square base and open top must have a volume of 78732 cm. We wish to find the dimensions of the box that
minimize the amount of material used.
First, find a formula for the surface area of the box in terms of only æ, the length of one side of the square base.
[Hint: use the volume formula to express the height of the box in terms of r.]
Simplify your formula as much as possible.
A(z) =
Next, find the derivative, A'(x).
A' (x) =
Now, calculate when the derivative equals zero, that is, when A (2)
0. [Hint: multiply both sides by a)
= 0 when I =
We next have to make sure that this value of z gives a minimum value for the surface area. Let's use the second derivative
test. Find A"(x).
A"(x) =
Evaluate A"(x) at the x-value you gave above.
NOTE: Since your last answer is positive, this means that the graph of A(x) is concave up around that value, so the
zero of A'(x) must indicate a local minimum for A(x). (Your boss is happy now.)
Submit Question
Transcribed Image Text:A box with a square base and open top must have a volume of 78732 cm. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only æ, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of r.] Simplify your formula as much as possible. A(z) = Next, find the derivative, A'(x). A' (x) = Now, calculate when the derivative equals zero, that is, when A (2) 0. [Hint: multiply both sides by a) = 0 when I = We next have to make sure that this value of z gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = Evaluate A"(x) at the x-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(x) is concave up around that value, so the zero of A'(x) must indicate a local minimum for A(x). (Your boss is happy now.) Submit Question
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