A box with a square base and open top must have a volume of 219488 cm°. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only x, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of x.] Simplify your formula as much as possible. A(x) = Next, find the derivative, A'(x). A' (x) = Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by x2.] A'(x) = 0 when x = We next have to make sure that this value of x gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) Evaluate A"(x) at the x-value you gave above.

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ISBN:9780470458365
Author:Erwin Kreyszig
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**Finding the Dimensions of a Box with Minimum Material**

A box with a square base and an open top must have a volume of \(219488 \, \text{cm}^3\). We wish to find the dimensions of the box that minimize the amount of material used.

**Step 1: Surface Area Formula**

First, find a formula for the surface area of the box in terms of only \(x\), the length of one side of the square base. 
*Hint: Use the volume formula to express the height of the box in terms of \(x\).*
Simplify your formula as much as possible.

\[ A(x) = \]

**Step 2: Derivative of Surface Area**

Next, find the derivative, \( A'(x) \).

\[ A'(x) = \]

**Step 3: Finding Critical Points**

Now, calculate when the derivative equals zero, that is, when \( A'(x) = 0 \).
*Hint: Multiply both sides by \( x^2 \).*

\[ A'(x) = 0 \text{ when } x = \]

**Step 4: Verify Minimum Surface Area**

We next have to make sure that this value of \(x\) gives a minimum value for the surface area. Let's use the second derivative test. Find \( A''(x) \).

\[ A''(x) = \]

**Step 5: Evaluating the Second Derivative**

Evaluate \( A''(x) \) at the \( x \)-value you gave above.
Transcribed Image Text:**Finding the Dimensions of a Box with Minimum Material** A box with a square base and an open top must have a volume of \(219488 \, \text{cm}^3\). We wish to find the dimensions of the box that minimize the amount of material used. **Step 1: Surface Area Formula** First, find a formula for the surface area of the box in terms of only \(x\), the length of one side of the square base. *Hint: Use the volume formula to express the height of the box in terms of \(x\).* Simplify your formula as much as possible. \[ A(x) = \] **Step 2: Derivative of Surface Area** Next, find the derivative, \( A'(x) \). \[ A'(x) = \] **Step 3: Finding Critical Points** Now, calculate when the derivative equals zero, that is, when \( A'(x) = 0 \). *Hint: Multiply both sides by \( x^2 \).* \[ A'(x) = 0 \text{ when } x = \] **Step 4: Verify Minimum Surface Area** We next have to make sure that this value of \(x\) gives a minimum value for the surface area. Let's use the second derivative test. Find \( A''(x) \). \[ A''(x) = \] **Step 5: Evaluating the Second Derivative** Evaluate \( A''(x) \) at the \( x \)-value you gave above.
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