A box of mass m moves a distance d across a horizontal floor, its speed increases due to a horizontal force acting on the box with magnitude Fapp. The magnitude of its acceleration is a, and the coefficients of kinetic and static friction between the box and floor are μ and ₂. Using the variables listed along with the acceleration due to gravity, g; write an expression for the total work done on the box. If the friction coefficients are μ = 0.25 and μ = 0.55 and if m= 8.56 kg, a = 2.02 m/s2, and d = 2.24 m then how much work in Joules is performed by friction? Using the same values listed in the previous question how much work, in Joules is performed by the applied force Fapp?
A box of mass m moves a distance d across a horizontal floor, its speed increases due to a horizontal force acting on the box with magnitude Fapp. The magnitude of its acceleration is a, and the coefficients of kinetic and static friction between the box and floor are μ and ₂. Using the variables listed along with the acceleration due to gravity, g; write an expression for the total work done on the box. If the friction coefficients are μ = 0.25 and μ = 0.55 and if m= 8.56 kg, a = 2.02 m/s2, and d = 2.24 m then how much work in Joules is performed by friction? Using the same values listed in the previous question how much work, in Joules is performed by the applied force Fapp?
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
Transcribed Image Text:**Problem Statement**
A box of mass \( m \) moves a distance \( d \) across a horizontal floor. Its speed increases due to a horizontal force acting on the box with magnitude \( F_{\text{app}} \). The magnitude of its acceleration is \( a \), and the coefficients of kinetic and static friction between the box and floor are \( \mu_k \) and \( \mu_s \).
Using the variables listed along with the acceleration due to gravity, \( g \); write an expression for the total work done on the box.
If the friction coefficients are \( \mu_k = 0.25 \) and \( \mu_s = 0.55 \) and if \( m = 8.56 \, \text{kg} \), \( a = 2.02 \, \text{m/s}^2 \), and \( d = 2.24 \, \text{m} \) then how much work in Joules is performed by friction?
Using the same values listed in the previous question, how much work, in Joules, is performed by the applied force \( F_{\text{app}} \)?
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