A box contains 10 cards numbered from 0 to 9. 1. In how many ways we can select 4 cards in order and without replacement. Final numerical answer: 10000 2. Find the probability that we select 3 cards, In order and without replacement, such that the first card is more than 5 and the third card is even. Answer: 144/720 3. If we we select 3 cards, In order and without replacement, find the probability that the sum of the cards is 8 glven that the first card is 7. Answer: 2/72

Q: 29(P − 34) = 464

A:

Q: 5n+34=-2(1-7)

A: Consider the following expression: 5n+34=-21-75n+34=-2×-65n+34=125n=12-345n=-22n=-225n=-4.4

Q: 32+4 to Le

A:

Q: 4y-12=0

A: 4y = 12 y = 3

Q: (-2) · (15 + 9) + (5 – 9 + 8)

A: Given: -2·15+9÷5-9+8

Q: 1 L (s- 4)6 J

A:

Q: 2. K 5x+5 16 35

A:

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: a2-7a+10=0

A: We have to factor 10 so that the sum of the factors = -710= -5 times -2 and -5 + (-2) =-7 too So we…

Q: L(P-5)0

A: Explanation of the answer is as follows

Q: 4b2 + 8b +7 = 4

A: Given that

Q: 5×-6=37

A: Given,           5×-6=37

Q: 3n+20=15

A: solve the given 3n+20=15

Q: x2+y2=25

A:

Q: 3=6

A: Suppose the empty box has value x than do the calculation.

Q: 3z-13-z+5=0

A: Given equation is

Q: Ys+1 s7105 +?4

A:

Q: (-2/3)(-6)+(-1 1/3)

A: Consider −23−6+−113

Q: 3 D P + 402-7P+2 =0

A:

Q: -7(-p + 9)+ 7=-p

A: Given  -7(-p + 9)+ 7=-p Find p?

Q: 2(a+3)= -12

A: Solution: Here 2(a+3) =-12

Q: S dr 3r+5 r3-8

A:

Q: 13-2+3

A: this is a simple calculation question we will simplify this by normal calculation.

Q: Q5/ Find A-в, if: 1 2 3 - 2 1 B = 2 A = 2 -1 0 1 3 - 1

A:

Q: K2  - 6k - 14 = -7

A: For the value of k, we have to factorise the given polynomial function.

Q: r+6/5 = r+8/7

A: We will use cross multiplication.

Q: k-2=10

A: Given equation is k-2=10 We have to find the value of k. Add both sides 2 and further simplify it…

Q: 2m + 8 = 56

A: We have to find m

Q: SVe -z) + 4 dz

A:

Q: z2-3z=-8

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.