A bowling ball that has a radius of 11.0 cm and a mass of 6.00 kg rolls without slipping on a level lane at 4.00 rad/s.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement**

A bowling ball that has a radius of 11.0 cm and a mass of 6.00 kg rolls without slipping on a level lane at 4.00 rad/s.

Calculate the ratio \( R \) of the translational kinetic energy to the rotational kinetic energy of the bowling ball.

\[ R = \]

---

**Explanation for Students**

This problem asks you to find the ratio of two different types of kinetic energy for a rolling bowling ball: translational and rotational. Here's what each term means:

- **Translational Kinetic Energy (TKE):** This is the energy due to the linear motion of the body's center of mass. It can be calculated using the formula \( \text{TKE} = \frac{1}{2} mv^2 \), where \( m \) is the mass and \( v \) is the linear velocity of the center of mass.

- **Rotational Kinetic Energy (RKE):** This is the energy due to the rotation of the body around its center of mass. It can be calculated with \( \text{RKE} = \frac{1}{2} I \omega^2 \), where \( I \) is the moment of inertia and \( \omega \) is the angular velocity.

To solve this:
1. Use the no-slip condition to relate linear velocity and angular velocity: \( v = r\omega \), where \( r \) is the radius.
2. The moment of inertia \( I \) for a solid sphere is \( \frac{2}{5} mr^2 \).
3. Substitute these into the TKE and RKE formulas to find their expressions.
4. Calculate the ratio \( R \) by dividing TKE by RKE.
Transcribed Image Text:**Problem Statement** A bowling ball that has a radius of 11.0 cm and a mass of 6.00 kg rolls without slipping on a level lane at 4.00 rad/s. Calculate the ratio \( R \) of the translational kinetic energy to the rotational kinetic energy of the bowling ball. \[ R = \] --- **Explanation for Students** This problem asks you to find the ratio of two different types of kinetic energy for a rolling bowling ball: translational and rotational. Here's what each term means: - **Translational Kinetic Energy (TKE):** This is the energy due to the linear motion of the body's center of mass. It can be calculated using the formula \( \text{TKE} = \frac{1}{2} mv^2 \), where \( m \) is the mass and \( v \) is the linear velocity of the center of mass. - **Rotational Kinetic Energy (RKE):** This is the energy due to the rotation of the body around its center of mass. It can be calculated with \( \text{RKE} = \frac{1}{2} I \omega^2 \), where \( I \) is the moment of inertia and \( \omega \) is the angular velocity. To solve this: 1. Use the no-slip condition to relate linear velocity and angular velocity: \( v = r\omega \), where \( r \) is the radius. 2. The moment of inertia \( I \) for a solid sphere is \( \frac{2}{5} mr^2 \). 3. Substitute these into the TKE and RKE formulas to find their expressions. 4. Calculate the ratio \( R \) by dividing TKE by RKE.
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