A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 56 specimens and counts the number of seeds in each. Use her sample results (mean = 36.4, standard deviation = 9.3) to find the 98% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.  98% C.I. =

Q: A geologist examine 16 seawater samples for mercury concentration. The main mercury concentration…

A:

Q: A sample of 15 Math SAT scores for women was collected. The mean score for the sample was 472 and…

A:

Q: Suppose you select a random sample of N=81, and find X = 50, and s = 9.9. Determine the 99%…

A: Given Mean=50 Standard deviations=9.9 n=81

Q: A sample of 16 Math SAT scores for women was collected. The mean score for the sample was 507 and…

A: Sample size n=16 Sample mean x=507 Sample standard deviation s=115 Confidence interval 95% The…

Q: Assume you select an SRS of size 94 and give them a test. You calculate the mean test score in your…

A:

Q: Choose a quantitative variable.  Measure it on two different samples of 10, drawn from two different…

A:

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Solution-: Given: x¯=83.97,n=76,σ=13.89  Use this information to construct the​ 90% and​ 95%…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given Data: Confidence level - 90%: The expression for the confidence level is,

Q: You measure 28 dogs' weights, and find they have a mean weight of 71 ounces. Assume the population…

A:

Q: In a certain population, let us assume that IQ scores are normally distributed with mean of 100 and…

A: A percentile is a comparison score between a specified score and the scores of the remaining data…

Q: A physicist examines 4 seawater samples for iron concentration. The mean iron concentration for the…

A: Given dataSample size(n) = 4Sample mean = 0.185 cc/cubicSample standard deviation =…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: if E=0.07 and population standard deviation=0.8 then find the sample size for 99% confidence…

A: Margin of error(E)=0.07 population standard deviation(σ)=0.8 confidence level=99%

Q: In a random sample of nine people, the mean driving distance to work was 25 miles the sample…

A:

Q: you are given the sample mean and the population standard deviation. Use this information to…

A:

Q: In a random sample of five ​people, the mean driving distance to work was 19.9 miles and the…

A: Given Sample size, n = 5 Degree of freedom, n-1 = 4 Sample mean, x = 19.9 miles Sample standard…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below                                E = Width2…

Q: A particular fruit's weights are normally distributed, with a mean of 712 grams and a standard…

A: Solution: Let X be the weight of a particular fruit. From the given information, X follows normal…

Q: The estimated prevalence is 11%, and the desired confidence level is 91% with a margin of error of…

A:

Q: You sample 40 dogs and find a sample mean weight of 60 lbs with a sample standard deviation of 5.…

A: From the provided information, Sample size (n) = 40 Sample mean (x̅) = 60 lbs Sample standard…

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X  ±  Z s √(n) Where: X is the mean Z is the Z-value…

Q: You measure 32 textbooks weight and find they have a mean weight of 67 ounces. Assume the standard…

A: Given: Sample size (n) = 32 Mean (x̄) = 67 ounces Population standard deviation (σ) = 8.302…

Q: The following table lists the income tax rates for a single person earning $50,000 per year for…

A:

Q: Construct a confidence interval of the population proportion at the given level of confidence. X =…

A:

Q: Which interval is wider? Choose the correct answer below. The 95% confidence interval O The 90%…

A: To construct 90% and 95% confidence intervals and answer the sub-parts.

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given Data: The sample size is: n=58 The mean temperature of the city is: μ=83.43 °F The standard…

Q: A sample of 17 Math SAT scores for women was collected. The mean score for the sample was 491 and…

A: Given Mean: x¯=491 Standard deviations: s=108 Sample size: n =17 Confidence interval: C.I.=0.95

Q: A statistics practitioner took a random sample of 47 observations from a population whose standard…

A: From the given information, it is clear that,  Sample mean X=99 Population standard deviation σ=27…

Q: Use the Empirical Rule to find the number of scores falling into each of the following intervals: a.…

A: The Empirical rule says that for bell- shaped distribution,  About 68% of observations lie within 1…

Q: There is a population of test scores. You take a sample of 11 scores and use them to estimate the…

A: From the given information, Sample size (n) =11 Assuming population is normally distributed with…

Q: This past yeal, through (e). A Click the icon to view the data table. (d) Explain why a large sample…

A: Given dataThis past year an organisation conducted a surveyThe results of the survey are shown

Q: Identify the data value corresponding to the indicated percentile. The amount of sleep an adult gets…

A: The normal distribution:A continuous random variable X is said to follow normal distribution with…

Q: The Gidget Company makes widgets. If the production process is working properly, it turns out that…

A: Given See the handwritten solution

Q: Construct a 90% confidence interval for the mean when x̅=50 and there are 31 observations. Suppose…

A:

Q: Find the margin of​ error, using a​ 95% confidence​ level, for estimating the percentage of all…

A: Given:- simple random sample of 1200 young people  so, n= 1200 86% had earned a high school diploma…

Q: Construct a 90​% confidence interval of the population proportion using the given information.…

A: x=240  n=300  p= 240/300 = 0.8 q = 1-p = 1-0.8 = 0.2

Q: The data given below gives the marks scored by six second year students taking BSc. Engineering: 87,…

A: From the provided information, Sample size (n) = 6 The sample mean and standard deviation can be…

Q: A student randomly selects 10 paperbacks at a store. The sample standard deviation is $1.50.…

A: Solution To find confidence interval we will use chi square distribution.

Q: In a study with lower quartile 100, upper quartile 140 and median as 130 How many people can have…

A:

Q: You sample 36 students to find out how many hours they spent online last week. Your sample mean is…

A: From the provided information, Sample size (n) = 36 Sample mean (x̅) = 54 Population standard…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.