- A booster club paid for pizzas for an end of season party. They paid $13 for each pepperoni pizza and $11 for each plain pizza. The club bought a total of 18 pizzas for the party and paid a total of $212. Drag and drop the numbers to the boxes to create an equation which models this situation if x = the number of pepperoni pizzas and y = the %3D number of plain pizzas bought.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 92E
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### Problem Analysis and Equation Formation

**Scenario Description:**

A booster club purchased pizzas for an end-of-season party. They incurred the following costs:
- $13 per pepperoni pizza
- $11 per plain pizza 

The total number of pizzas bought was 18, and the total expenditure was $212.

**Task:**

Form an equation that models the situation described above. Let:
- \( x \) represent the number of pepperoni pizzas
- \( y \) represent the number of plain pizzas

**Step-by-Step Solution:**

1. **Identify the costs:**
   - Cost of one pepperoni pizza (\( x \)) = $13
   - Cost of one plain pizza (\( y \)) = $11

2. **Set up the equation:**
   - The number of pepperoni pizzas (\( x \)) multiplied by its unit price ($13) plus the number of plain pizzas (\( y \)) multiplied by its unit price ($11) should equal the total amount spent ($212).

The equation to model this scenario is:
\[ 13x + 11y = 212 \]

**Drag and Drop Instructions:**
Drag and drop the appropriate numbers into the boxes to create the correct equation.

\[ \_\_\_\_ x + \_\_\_\_ y = 212 \]

**Options Available for Drag and Drop:**
- 10
- 11
- 12
- 13
- 14
- 15

***Correct Solution:***
\[ 13x + 11y = 212 \]

**Graphical Description:**
There are no graphs or diagrams in the given text. The instructions revolve around creating an equation to model a given real-world problem regarding the purchase of pizzas.

**Educational Notes:**
This problem helps students apply algebraic thinking to form and solve equations based on real-life scenarios, reinforcing the concepts of linear equations and cost analysis.
Transcribed Image Text:### Problem Analysis and Equation Formation **Scenario Description:** A booster club purchased pizzas for an end-of-season party. They incurred the following costs: - $13 per pepperoni pizza - $11 per plain pizza The total number of pizzas bought was 18, and the total expenditure was $212. **Task:** Form an equation that models the situation described above. Let: - \( x \) represent the number of pepperoni pizzas - \( y \) represent the number of plain pizzas **Step-by-Step Solution:** 1. **Identify the costs:** - Cost of one pepperoni pizza (\( x \)) = $13 - Cost of one plain pizza (\( y \)) = $11 2. **Set up the equation:** - The number of pepperoni pizzas (\( x \)) multiplied by its unit price ($13) plus the number of plain pizzas (\( y \)) multiplied by its unit price ($11) should equal the total amount spent ($212). The equation to model this scenario is: \[ 13x + 11y = 212 \] **Drag and Drop Instructions:** Drag and drop the appropriate numbers into the boxes to create the correct equation. \[ \_\_\_\_ x + \_\_\_\_ y = 212 \] **Options Available for Drag and Drop:** - 10 - 11 - 12 - 13 - 14 - 15 ***Correct Solution:*** \[ 13x + 11y = 212 \] **Graphical Description:** There are no graphs or diagrams in the given text. The instructions revolve around creating an equation to model a given real-world problem regarding the purchase of pizzas. **Educational Notes:** This problem helps students apply algebraic thinking to form and solve equations based on real-life scenarios, reinforcing the concepts of linear equations and cost analysis.
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