- A booster club paid for pizzas for an end of season party. They paid $13 for each pepperoni pizza and $11 for each plain pizza. The club bought a total of 18 pizzas for the party and paid a total of $212. Drag and drop the numbers to the boxes to create an equation which models this situation if x = the number of pepperoni pizzas and y = the %3D number of plain pizzas bought.
- A booster club paid for pizzas for an end of season party. They paid $13 for each pepperoni pizza and $11 for each plain pizza. The club bought a total of 18 pizzas for the party and paid a total of $212. Drag and drop the numbers to the boxes to create an equation which models this situation if x = the number of pepperoni pizzas and y = the %3D number of plain pizzas bought.
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 92E
Related questions
Question
![### Problem Analysis and Equation Formation
**Scenario Description:**
A booster club purchased pizzas for an end-of-season party. They incurred the following costs:
- $13 per pepperoni pizza
- $11 per plain pizza
The total number of pizzas bought was 18, and the total expenditure was $212.
**Task:**
Form an equation that models the situation described above. Let:
- \( x \) represent the number of pepperoni pizzas
- \( y \) represent the number of plain pizzas
**Step-by-Step Solution:**
1. **Identify the costs:**
- Cost of one pepperoni pizza (\( x \)) = $13
- Cost of one plain pizza (\( y \)) = $11
2. **Set up the equation:**
- The number of pepperoni pizzas (\( x \)) multiplied by its unit price ($13) plus the number of plain pizzas (\( y \)) multiplied by its unit price ($11) should equal the total amount spent ($212).
The equation to model this scenario is:
\[ 13x + 11y = 212 \]
**Drag and Drop Instructions:**
Drag and drop the appropriate numbers into the boxes to create the correct equation.
\[ \_\_\_\_ x + \_\_\_\_ y = 212 \]
**Options Available for Drag and Drop:**
- 10
- 11
- 12
- 13
- 14
- 15
***Correct Solution:***
\[ 13x + 11y = 212 \]
**Graphical Description:**
There are no graphs or diagrams in the given text. The instructions revolve around creating an equation to model a given real-world problem regarding the purchase of pizzas.
**Educational Notes:**
This problem helps students apply algebraic thinking to form and solve equations based on real-life scenarios, reinforcing the concepts of linear equations and cost analysis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F147df919-211a-4f6b-8a08-93da42538ff3%2F74b93fe9-cc48-477b-ad63-ec0488377e19%2Fthiqgta_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Analysis and Equation Formation
**Scenario Description:**
A booster club purchased pizzas for an end-of-season party. They incurred the following costs:
- $13 per pepperoni pizza
- $11 per plain pizza
The total number of pizzas bought was 18, and the total expenditure was $212.
**Task:**
Form an equation that models the situation described above. Let:
- \( x \) represent the number of pepperoni pizzas
- \( y \) represent the number of plain pizzas
**Step-by-Step Solution:**
1. **Identify the costs:**
- Cost of one pepperoni pizza (\( x \)) = $13
- Cost of one plain pizza (\( y \)) = $11
2. **Set up the equation:**
- The number of pepperoni pizzas (\( x \)) multiplied by its unit price ($13) plus the number of plain pizzas (\( y \)) multiplied by its unit price ($11) should equal the total amount spent ($212).
The equation to model this scenario is:
\[ 13x + 11y = 212 \]
**Drag and Drop Instructions:**
Drag and drop the appropriate numbers into the boxes to create the correct equation.
\[ \_\_\_\_ x + \_\_\_\_ y = 212 \]
**Options Available for Drag and Drop:**
- 10
- 11
- 12
- 13
- 14
- 15
***Correct Solution:***
\[ 13x + 11y = 212 \]
**Graphical Description:**
There are no graphs or diagrams in the given text. The instructions revolve around creating an equation to model a given real-world problem regarding the purchase of pizzas.
**Educational Notes:**
This problem helps students apply algebraic thinking to form and solve equations based on real-life scenarios, reinforcing the concepts of linear equations and cost analysis.
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