A book about college reports that the mean time students study each week is 1015 minutes. A dean says she believes the mean is greater than 1015 minutes. Suppose she takes a random sample of 64 students and finds that the sample mean is 1050 minutes. Assume the population standard deviation is 150 minutes. Test the deans claim at a = 0.05. Use this scenario to answer questions 6-10 6) State the alternative and null hypothesis 7) Calculate the test statistic

Q: Šolve for x. 10x + 14 Вх - 23

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Q: can you explain the first few questions aswell

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Q: part c parked as wrong answer

A: Mean()=12Standard deviation()=4

Q: Solve. 3 =D2 518 4.

A: Given. A linear equation in X such that 3X/4 + 5/8 = 2

Q: Need questions 4 5 and 6 answered please

A: 4. Given: μ=70, σ=5 The corresponding z-values needed to be computed: The probability that a score…

Q: This answer is incorrect. Can you try again?

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Q: Question 4 too please.

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Q: 3. Solve for x.

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Q: Is this for question 2 or 3?

A: The standard deviation is 0.2.

Q: 4. X = 100

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Q: 1.

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Q: what about questions 4-15?

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Q: Question 9

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Q: 2. 9=x-2y 3x + 5 = 2y

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Q: do question 7

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Q: 3. solve the limeor d.cle ý+ 3y= e"

A: Solution: The objective is to find the general solution to the given differential equation

Q: Can someone complete question 2

A: The given function is:f(x,y)=(x+5)eyGiven point is:P=(3, 0)