A body of mass 8 kg moves in the xy-plane in a counterclockwise circular path of radius 3 meters centered at the origin, making one revolution every 10 seconds. At the time t=0, the body is at the rightmost point of the circle. A. Compute the centripetal force acting on the body at time t. ⟨, ⟩ B. Compute the magnitude of that force.  HINT. Start with finding the angular velocity w [rad/s] of the body (the rate of change of its polar angle w.r.t. the center of rotation). Then find the position vector r→(t) of the body at time t. Then find its acceleration vector a→(t) at time t. Then use Newton's 2nd law to find the centripetal force F→(t).

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A body of mass 8 kg moves in the xy-plane in a counterclockwise circular path of radius 3 meters centered at the origin, making one revolution every 10 seconds. At the time t=0, the body is at the rightmost point of the circle.
A. Compute the centripetal force acting on the body at time t.
⟨, ⟩
B. Compute the magnitude of that force. 

HINT. Start with finding the angular velocity w [rad/s] of the body (the rate of change of its polar angle w.r.t. the center of rotation).
Then find the position vector r→(t) of the body at time t.
Then find its acceleration vector a→(t) at time t.
Then use Newton's 2nd law to find the centripetal force F→(t).

Expert Solution
Step 1

Given,

First, let's find the angular velocity of the body. Since the body makes one revolution every 10 seconds, its angular velocity is: ω =2π rad10 s =π5 rad/s

Next, let's find the position vector r→(t) of the body at time t. Since the body starts at the rightmost point of the circle, its position vector at time t is:

r→(t) = (3 cos(ωt))i + (3 sin(ωt))j

where i and j are the unit vectors in the x- and y-directions, respectively.

 

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