A body is taken below the surface of the earth at a depth of 18 km. Find the percentage decrease in weight of the body. (Given = 6400 km)
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Q: The weight w of an object varied inversely as the square of the distance d between the object and…
A: Given: W1= 90 kg r1= 6400 km W2= weight of the man at 400 km r2= 400 km
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A: Density is a measure of mass per volume. Density = mass/volume So, Mass = density × volume
Q: Problem 5 An 18-N weight is held by two strings, as show. What are both tensions T₁ and T₂?
A: Weight=18 Nvalues of T1 and. T2values of T1 and. T2
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Q: If cylinder E weights 30 lb and θ =15°,determine the weight of the cylinder F
A: Given data: The weight of cylinder is w=30 lb. The angle is θ=15°.
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A: The gravitational acceleration at height h above the Earth's surface is given by, g'= g(1+hR)2
Q: If an object weighs 3 x 105 N on the surface of the earth, what would its weight be at an altitude…
A: R is radius of earth , R = 6400 km
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Q: Fnorm (normal force) = _________ N Ffrict (force of friction) = _________ N Fgrav (force of…
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Q: A net force of 16 N [40° W of N] is caused by two applied forces acting on the same object. These…
A: Given : net force = 16 N which has angle of 40 with west axis in direction of north . Find…
Q: A volleyball player applies an average force of 9.9 N [33 degrees above the horizontal]. The force…
A: Given Data : The force due to the volleyball player is given as F1=9.9 N The force due to gravity is…
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Q: shown below. The left-hand cable had tension 590 N and makes an angle of 0 with the wall. The…
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