A block with mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 25.0 kg and moment of inertia 0.500 2 . kg m² with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.200 m from that axis.
A block with mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 25.0 kg and moment of inertia 0.500 2 . kg m² with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.200 m from that axis.
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Transcribed Image Text:A block with mass m = 5.00 kg slides down a surface
inclined 36.9° to the horizontal (Figure 1). The coefficient
of kinetic friction is 0.27. A string attached to the block is
wrapped around a flywheel on a fixed axis at O. The
flywheel has mass 25.0 kg and moment of inertia 0.500
kg m² with respect to the axis of rotation. The string
.
pulls without slipping at a perpendicular distance of 0.200
Im from that axis.
5.00 kg
36.9°

Transcribed Image Text:▼
Part A
What is the acceleration of the block down the plane?
Express your answer in meters per second squared.
5 ΑΣΦ
a=
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Part B
X Incorrect; Try Again; 9 attempts remaining
What is the tension in the string?
Express your answer in newtons.
T=
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ESSERE
VE ΑΣΦ
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?
?
m/s²
N
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