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A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (the figure (Figure 1)). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant kis 100 N/m. Part A What is the coefficient of kinetic friction between the block and the tabletop? Express your answer using two significant figures. = 041

A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (the figure (Figure 1)). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant kis 100 N/m. Part A What is the coefficient of kinetic friction between the block and the tabletop? Express your answer using two significant figures. = 041

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Please solve part A (ignore that its already solved) using the equations i added as an accompaning file. 

A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (the figure (Figure 1)). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant kis 100 N/m. Figure k = 100 N/m 0.20 m 1.00 m 1 of 1 m = 0.50 kg Part A What is the coefficient of kinetic friction between the block and the tabletop? Express your answer using two significant figures. 4k = 0.41 Submit Previous Answers Correct Correct answer is shown. Your answer 0.4 was either rounded differently or used a different required for this part. Provide Feedback
Transcribed Image Text:A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (the figure (Figure 1)). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant kis 100 N/m. Figure k = 100 N/m 0.20 m 1.00 m 1 of 1 m = 0.50 kg Part A What is the coefficient of kinetic friction between the block and the tabletop? Express your answer using two significant figures. 4k = 0.41 Submit Previous Answers Correct Correct answer is shown. Your answer 0.4 was either rounded differently or used a different required for this part. Provide Feedback
Chapter 7 where also where K=/m² WG = -AUG = -AUay and W, =W₁ = -AU, = -AUel where (with up as the positive direction): Uc = Ugray = mgy_and U₁ = U₁ = ² W = Fscos F= F if F= constant Fnet & Cos= AK Whet = and Wuet = or equivalently: W₁otal Wr₁ + W₂+. Wotal AK ** Wae= Wother = AE = Ey - E₁ EK+U If We Wother = 0. then E, E = K₁ +U₁=K₁ + U₁ + Wac K₁+U₂ + Wother AW P= P₁==F₁0 At
Transcribed Image Text:Chapter 7 where also where K=/m² WG = -AUG = -AUay and W, =W₁ = -AU, = -AUel where (with up as the positive direction): Uc = Ugray = mgy_and U₁ = U₁ = ² W = Fscos F= F if F= constant Fnet & Cos= AK Whet = and Wuet = or equivalently: W₁otal Wr₁ + W₂+. Wotal AK ** Wae= Wother = AE = Ey - E₁ EK+U If We Wother = 0. then E, E = K₁ +U₁=K₁ + U₁ + Wac K₁+U₂ + Wother AW P= P₁==F₁0 At
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