A block weights 150g and it’s attached to a 0.6m long string. The block starts from rest and begins to spin in a circle accelerating at a constant rate of 0.25 rad/s^2 on a horizontal surfaces if the string has a max tension of 5N. How long does it take for the string to break? How many revolutions did the block complete? Please Use the equations provided.
A block weights 150g and it’s attached to a 0.6m long string. The block starts from rest and begins to spin in a circle accelerating at a constant rate of 0.25 rad/s^2 on a horizontal surfaces if the string has a max tension of 5N. How long does it take for the string to break? How many revolutions did the block complete? Please Use the equations provided.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A block weights 150g and it’s attached to a 0.6m long string. The block starts from rest and begins to spin in a circle accelerating at a constant rate of 0.25 rad/s^2 on a horizontal surfaces if the string has a max tension of 5N. How long does it take for the string to break? How many revolutions did the block complete?
Please Use the equations provided.

Transcribed Image Text:Equations:
Vector components, standard Cartesian plane:
Vx= V cos 8
Vy = V sin 0
Constant linear acceleration:
V = Vo + at
Projectile motion:
X = Xo + Voxt
Rotational motion:
0 = s/r
@= @o + at
Frictional force:
w = v/r
Newton's Second Law of motion:
Centripetal force:
Use g
d = do + Vot + ½ at²
Gravitational force, or weight:
=
Vx² + Vy² = V²
y = yo + Voy - 1/2 gt²
360⁰ = 2n radians
a = aT/r
000+ wot + ½ at²
tan 8 = Vy/Vx
v² = vo² + 2a(d-do)
Vy = Voy -gt
ac = v²/r = rw²
w² = wo² + 2a(0 - 0)
ΣF = ma
Fg = mg
Ff = µFn
Fc = mv²/r
10.0 m/s² for the acceleration due to gravity near the surface of the earth.
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