A block of wood of mass 2 kg is placed over the muzzle of a rifle, and a bullet of mass 25 g is fired vertically upward. The bullet embeds in the wood, which rises to a macimum height of 3 m. Calculate the muzzle velocity of the bullet

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Chapter1: Units, Trigonometry. And Vectors
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A block of wood of mass 2 kg is placed over the muzzle of a rifle, and a bullet of mass 25 g is fired vertically upward. The bullet embeds in the wood, which rises to a macimum height of 3 m. Calculate the muzzle velocity of the bullet.

 

 

**Example of a Hanging Object on a Spring**

In the provided illustration, we observe an example of a hanging object attached to a spring, commonly used in physics to demonstrate principles such as Hooke's Law and gravitational force.

**Description:**

1. **Object and Spring Arrangement:**
   - There is an oblong-shaped object attached to a horizontal spring.
   - The object appears to have a mass of 2 kg, as indicated in the diagram.
   - The object is hanging freely under the influence of gravity.
   - The spring is anchored to a fixed support at the top.

2. **Dimensions:**
   - The distance between the top fixed support of the spring and the bottom of the mass is marked as 3 meters.

**Understanding the Setup:**

- This setup is often used to calculate the force exerted by the spring (spring force), which can be done using Hooke's Law:
\[
F = -kx
\]
  Where:
   \[
   F \text{ is the force exerted by the spring}, \\
   k \text{ is the spring constant}, \\
   x \text{ is the extension or compression of the spring from its natural length}.
\]

- Gravitational force acting on the mass can be calculated using:
\[
F = mg 
\]
  Where:
   \[
   m \text{ is the mass}, \\
   g \text{ is the acceleration due to gravity (approximately 9.8 m/s}^2\text{)}.
\]

In this case, the gravitational force acting on the 2 kg mass would be:
\[
F = 2 \text{ kg} \times 9.8 \text{ m/s}^2 = 19.6 \text{ N}
\]

- When the system is at equilibrium, the spring force equals the gravitational force, allowing the solving for variables such as the spring constant \( k \).

This diagram and its interpretation can help in understanding basic mechanical principles, particularly related to elastic forces, oscillations, and energy conservation in physics.
Transcribed Image Text:**Example of a Hanging Object on a Spring** In the provided illustration, we observe an example of a hanging object attached to a spring, commonly used in physics to demonstrate principles such as Hooke's Law and gravitational force. **Description:** 1. **Object and Spring Arrangement:** - There is an oblong-shaped object attached to a horizontal spring. - The object appears to have a mass of 2 kg, as indicated in the diagram. - The object is hanging freely under the influence of gravity. - The spring is anchored to a fixed support at the top. 2. **Dimensions:** - The distance between the top fixed support of the spring and the bottom of the mass is marked as 3 meters. **Understanding the Setup:** - This setup is often used to calculate the force exerted by the spring (spring force), which can be done using Hooke's Law: \[ F = -kx \] Where: \[ F \text{ is the force exerted by the spring}, \\ k \text{ is the spring constant}, \\ x \text{ is the extension or compression of the spring from its natural length}. \] - Gravitational force acting on the mass can be calculated using: \[ F = mg \] Where: \[ m \text{ is the mass}, \\ g \text{ is the acceleration due to gravity (approximately 9.8 m/s}^2\text{)}. \] In this case, the gravitational force acting on the 2 kg mass would be: \[ F = 2 \text{ kg} \times 9.8 \text{ m/s}^2 = 19.6 \text{ N} \] - When the system is at equilibrium, the spring force equals the gravitational force, allowing the solving for variables such as the spring constant \( k \). This diagram and its interpretation can help in understanding basic mechanical principles, particularly related to elastic forces, oscillations, and energy conservation in physics.
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