Answered: A block of mass mm = 16 kgkg has a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A block of mass mm = 16 kgkg has a speed VV and is behind a block of mass MM = 65 kgkg that has a speed of 0.5 m/sm/s. The surface is frictionless. The blocks collide and couple. After the collision, the blocks have a common speed of 0.9 m/sm/s. In the figure, the loss of kinetic energy of the blocks due to the collision is closest to:

7.7 J

25 J

26 J

9.3 J

76 J

Expert Solution

Step 1

Using the conservation of momentum,

$\begin{array}{rcl} m_{1} {(v_{1})}_{i} + m_{1} {(v_{1})}_{i} & = & (m_{1} + m_{2}) v_{f} \\ (16 kg) {(v_{1})}_{i} + (65 kg) (0.5 {m.s}^{- 1}) & = & (16 kg + 65 kg) (0.9 {m.s}^{- 1}) \\ {(v_{1})}_{i} & = & 2.525 {m.s}^{- 1} \end{array}$

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