A block of mass m slides down an inclined plane with angle of inclination 30 degree with acceleration (a=g/3). Find the coefficient of friction.
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A: GIVEN Mass of block =m=3.97 kg magnitude of force =F=30N θ =…
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A: Given: The angle of the inclination is 20o. The coefficient of the friction is 0.33.
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A: Given, mass of block(m)= 13 kg L= 6.9 m h= 3.15 m µs= 0.085
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Q: A student of mass 63.4 kg, starting at rest, slides down a slide 20.2 m long, tilted at an angle of…
A: Given: A student of mass 63.4 kg, starting at rest, slides down a slide 20.2 m long, tilted at an…
Q: A block of mass m = 16.5 kg rests on an inclined plane with a coefficient of static friction of us =…
A: Part a] Angle theta made by plane = arcsin(h/L) = arcsin(3.05/6.8) = 27.5412 degreesPart b] FN = mg…
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A: Concept: The Free Body diagram of the system is given below: Given: Mass of the sphere (m)=4×10-4…
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A: Mass of sphere (m) = 4.7×10-4 kg Angle (θ) = 26o
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A: Draw the free-body diagram of the upper block.
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A: Resultant of forces can be determined by resolving the forces into its components.
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