A block of mass m B is being pulled up by a constant force Fpand is accelerating downwards (refer to the diagram and coordinate system below). X y B Which of the following statements are correct for the forces in Y direction: ΟΣ F = mpg - Fp = 0 ΟΣ F = 0

A block of mass m B is being pulled up by a constant force Fpand is accelerating downwards (refer to the diagram and coordinate system below). X y B Which of the following statements are correct for the forces in Y direction: ΟΣ F = mpg - Fp = 0 ΟΣ F = 0

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

dler?action=activityBranding&COURSEID=3377&SECTIONID=170728 1 2 1 2 art 1 art 2 $ X R F V 1. Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m, and the hanging mass is m₂. The table and the pulley are frictionless. O 15 % 5 T 2 7 Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m₁. ^ B 10 6 Y G H & M- 7 hp U fa J m₁ * 00 8 N M 1 IAA ( 9 K < fo O ► 11 0 O L m₂ f11 3 P ; 22 112 Rain.... ^ 40) @ { + [ ? = 12 ☆ 1 insert ( } ← ] S 4:45 PM 9/27/2022 prt sc backspace pause E
Two objects (m1=11.0 kg and m2=3.00 kg) are separated by 40.0 cm. A third object (m3=1.00 kg) is placed at a location along the line connecting them such that the net force acting on it is zero. By considering the force vectors, this location must be between the two original objects. We will define x as the distance between m1 and m3 and y as the distance between m2 and m3. 1) Find the distance between 11.0-kg object and 1.00-kg object along the line AB where a small, 1.00-kg object could rest such that the net gravitational force on it due to the two objects shown is exactly zero. (Express your answer to two significant figures.)
Please circle answers
60° 30° A 50 kg truck engine is lifted using the setup shown. Assuming that the pulleys are frictionless, What force P must be applied to the cable to hold the engine in the position shown with d= 1m? (Hint: because the frictionless pulleys, the tension in the cable will be uniform through out the whole length of the cable.) 2. 3. d 30 kg 600 N/m A 3m 3m Determine the reactions at A and B. 50 kg
Pls help ASAP
The frame has an original loading system of four applied forces and one applied couple moment. Replace this loading system by an equivalent resultant force and couple moment acting at point B. 1 (FR), (MR)B, B F, F3 B A (FR), d3 F4 da Original System Equivalent System Assume the following values: di = 0.990 m , d2 = 1.14 m , d3 = 0.540 m , d4 = 2.08 m , Fi = 502 N , F2 = 300 N, F = 508 N , F4 = 402 N , and MA = 1507 N - m Express the Cartesian components of the resultant force and the couple moment in newtons and newton-meters to three significant figures separated by commas. • View Available Hint(s) Πνα ΑΣφ I | vec (FR)1, (FR)y, (MR)B = N, N , Ν.m
Two blocks of masses m, = 4.0 kg and mg = 8.0 kg are connected with a string that passes over a very light pulley (Figure 1). Friction in the pulley can be ignored. Block 1 is resting on a rough table and block 2 is hanging over the edge. The coefficient of friction between the block 1 and the table is 0.70 (assume static and kinetic friction have the same value). Block 1 is also connected to a spring with a constant 300 N/m. In the initial state, the spring is relaxed as a person is holding block 2, but the string is still taut. When block 2 is released, it moves down for a distanced until it stops (the final state). Figure 1 of 1
Consider an object of mass m being pushed up a frictionless incline of angle theta by a force F parallel to the ground (not the incline). If the object is moving at a constant velocity, the expression for F in terms of m, g (the acceleration due to gravity near the earth's surface, leave it as a letter), and theta is______ (The outcome that I found was F=MgTan(theta) The “not the incline” it confuses me
A 2-kg hanging mass (m,) is connected by a string over a pulley to a 20-kg block (m,) that is sliding on a 30° fixed inclined plane (see the figure below). If the pulley's mass and the mass of the string are negligible, and all surfaces are frictionless, the magnitude of the acceleration (in m/s?) of the moving system is: A. 7.14 В. 9.8 С. 5.93 D. 3.56 E. 0.48
A particle of mass m moves down the inner surface of a hemisphere without friction. Find the equations of motion.
A skater of mass m standing on ice throws a stone of mass M with speed v in a horizontal direction. Find the distance over which the skater will move in the opposite direction if the coefficient of kinetic friction between the skater and the ice is ?k . (Use any variable or symbol stated above along with the following as necessary: g.)Δx =
Figure 1 В А Three blocks, labeled A, B, and C, are connected by essentially massless strings that run over essentially massless and frictionless pulleys (as shown in Figure A above). Block A hangs straight down. The string from block A connects to block B which is sliding up and to the left along an inclined plane. The plane is inclined at an angle of theta = 0 = 52 degrees away from vertical. The coefficient of kinetic friction between block B and the plane is 0.38. Block B is connected by a different string to block C which hangs straight down. Block A has a mass of 4.1 kg. Block B has a mass of 3.7 kg. Block C has a mass of 2.5 kg. Block A is moving down and block C is moving up (the strings do not stretch). The only significant forces acting on the blocks are friction acting on block B, normal forces, tension forces, and gravity (with g = 9.81 m/s²). Calculate the %3D acceleration (in units of meters per second squared) of block A. For block A, a downward acceleration is…