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A block of mass m = 5.00 kg slides down a ramp with a constant speed v = 3.00 m/s. The ramp is 1.500 m long and 0.500 m high. How much thermal energy, in joules, was generated as the box slid down from the top to the bottom of the ramp at constant speed? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. 1.50 m m= 5.00 kg v = 3.00 m/s = constant %3D 0.50 m

A block of mass m = 5.00 kg slides down a ramp with a constant speed v = 3.00 m/s. The ramp is 1.500 m long and 0.500 m high. How much thermal energy, in joules, was generated as the box slid down from the top to the bottom of the ramp at constant speed? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. 1.50 m m= 5.00 kg v = 3.00 m/s = constant %3D 0.50 m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Explain why 24.5 is the correct answer

### Problem Description A block of mass \( m = 5.00 \, \text{kg} \) slides down a ramp with a constant speed \( v = 3.00 \, \text{m/s} \). The ramp is \( 1.500 \, \text{m} \) long and \( 0.500 \, \text{m} \) high. How much thermal energy, in joules, was generated as the box slid down from the top to the bottom of the ramp at constant speed? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. ### Diagram Explanation The diagram shows: - A ramp inclined at an angle with the horizontal ground. - The ramp is labeled with a length of \( 1.50 \, \text{m} \) and a height of \( 0.50 \, \text{m} \). - At the top of the ramp, there is a block labeled \( m = 5.00 \, \text{kg} \). - An arrow along the ramp illustrates the direction of motion with a velocity labeled \( v = 3.00 \, \text{m/s} \, = \) constant. - The block is shown sliding down the ramp. ### Answer Box A numerical box is provided with an entry of "24." Below, it is noted that the exact answer is "24.5 (with margin: 0.025)." The focus is on determining the thermal energy generated due to the block sliding down the ramp at constant speed. This would involve calculating the gravitational potential energy loss and interpreting it as thermal energy since kinetic energy remains constant.
Transcribed Image Text:### Problem Description A block of mass \( m = 5.00 \, \text{kg} \) slides down a ramp with a constant speed \( v = 3.00 \, \text{m/s} \). The ramp is \( 1.500 \, \text{m} \) long and \( 0.500 \, \text{m} \) high. How much thermal energy, in joules, was generated as the box slid down from the top to the bottom of the ramp at constant speed? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. ### Diagram Explanation The diagram shows: - A ramp inclined at an angle with the horizontal ground. - The ramp is labeled with a length of \( 1.50 \, \text{m} \) and a height of \( 0.50 \, \text{m} \). - At the top of the ramp, there is a block labeled \( m = 5.00 \, \text{kg} \). - An arrow along the ramp illustrates the direction of motion with a velocity labeled \( v = 3.00 \, \text{m/s} \, = \) constant. - The block is shown sliding down the ramp. ### Answer Box A numerical box is provided with an entry of "24." Below, it is noted that the exact answer is "24.5 (with margin: 0.025)." The focus is on determining the thermal energy generated due to the block sliding down the ramp at constant speed. This would involve calculating the gravitational potential energy loss and interpreting it as thermal energy since kinetic energy remains constant.
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