A block of mass 2 kg is moving to the right with velocity V= 25 m/s. The block then compresses the spring until it finally stops. The spring is compressed by an amount of A X= 0.5 m. Use conservation of energy to find the spring constant.

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## Problem Statement

A block of mass 2 kg is moving to the right with a velocity \( V = 25 \, \text{m/s} \). The block then compresses the spring until it finally stops. The spring is compressed by an amount of \( \Delta X = 0.5 \, \text{m} \). Use conservation of energy to find the spring constant.

## Graph/Diagram

The image shows a rectangle (representing the block) on the left side, moving to the right. On the right side, there is a compressed spring that appears to stop the block. The spring is shown in its compressed state with a line indicating the point where the block comes to rest.

**Analysis Approach:**

1. **Initial Kinetic Energy of the Block**:
   \[
   KE_i = \frac{1}{2} m v^2 = \frac{1}{2} \times 2 \, \text{kg} \times (25 \, \text{m/s})^2 = 625 \, \text{J}
   \]

2. **Final Potential Energy in the Spring**:
   \[
   PE_f = \frac{1}{2} k (\Delta X)^2
   \]

3. **Conservation of Energy**:
   The initial kinetic energy of the block is converted completely into potential energy of the spring:
   \[
   KE_i = PE_f \Rightarrow 625 \, \text{J} = \frac{1}{2} k (0.5 \, \text{m})^2
   \]

4. **Solving for the Spring Constant \( k \)**:
   Rearrange and solve for \( k \):
   \[
   625 = \frac{1}{2} k \times 0.25
   \]
   \[
   625 = 0.125k
   \]
   \[
   k = \frac{625}{0.125} = 5000 \, \text{N/m}
   \]

In summary, using conservation of energy principles, the spring constant \( k \) is calculated to be 5000 N/m.
Transcribed Image Text:## Problem Statement A block of mass 2 kg is moving to the right with a velocity \( V = 25 \, \text{m/s} \). The block then compresses the spring until it finally stops. The spring is compressed by an amount of \( \Delta X = 0.5 \, \text{m} \). Use conservation of energy to find the spring constant. ## Graph/Diagram The image shows a rectangle (representing the block) on the left side, moving to the right. On the right side, there is a compressed spring that appears to stop the block. The spring is shown in its compressed state with a line indicating the point where the block comes to rest. **Analysis Approach:** 1. **Initial Kinetic Energy of the Block**: \[ KE_i = \frac{1}{2} m v^2 = \frac{1}{2} \times 2 \, \text{kg} \times (25 \, \text{m/s})^2 = 625 \, \text{J} \] 2. **Final Potential Energy in the Spring**: \[ PE_f = \frac{1}{2} k (\Delta X)^2 \] 3. **Conservation of Energy**: The initial kinetic energy of the block is converted completely into potential energy of the spring: \[ KE_i = PE_f \Rightarrow 625 \, \text{J} = \frac{1}{2} k (0.5 \, \text{m})^2 \] 4. **Solving for the Spring Constant \( k \)**: Rearrange and solve for \( k \): \[ 625 = \frac{1}{2} k \times 0.25 \] \[ 625 = 0.125k \] \[ k = \frac{625}{0.125} = 5000 \, \text{N/m} \] In summary, using conservation of energy principles, the spring constant \( k \) is calculated to be 5000 N/m.
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