A block of copper(0.230+mol) starts at 15.5 degrees Celsius. What is the final temperature of cu if 226 cal of heat are added to it?

Q: What is the specific heat of a 65.51 g piece of an unknown metal that exhibits a 45.2°C temperature…

A: Weight of unknown metal= 65.5 1g Temperature (∆T)= 45.2°C Absorbed heat=1870 J

Q: Mercury was once used in thermometers and barometers. When 69.7 J of heat are absorbed by 100.0 g of…

A: Given, Heat absorbed Q = 69.7 J change in temperature ΔT = 29.98 - 25 = 4.98 ℃ Mass m = 100 g

Q: What is the specific heat of a 1,500.00 gram sample of wood that absorbs 67,500 Joules of heat…

A: The given data contains, mass = 1500 g. Heat = 67500 Joules.

Q: In the laboratory a student finds that it takes 230 Joules to increase the temperature of 13.9 grams…

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Q: What is the specific heat of a 66.51 g piece of an unknown metal that exhibits a 45.2°C temperature…

A: The relation between specific heat and heat energy is given by q = m * C * ΔT Where q = heat energy…

Q: In the laboratory a student finds that it takes 75.4 Joules to increase the temperature of 13.3…

A: Specific heat capacity is the amount of heat that is required to rise a temperature of 1 kg…

Q: A chunck of lead at 91.7 degrees celcius was added to 200.0 g of water at 15.5 celcius. the specific…

A: Given:Specific heat of water = 4.18 J/goCspecific heat of lead = 0.129 J/goCInitial Temperature of…

Q: How much would the temperature of 295 g of water increase if 17.4 kJ of heat were added? (the…

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Q: A 50.0 g sample of scandium, Sc, is heated by exposure to 1.50 x 10J. The temperature of the Sc is…

A: When scandium is heated then it temperature increases. Total heat absorbed by metal is calculate…

Q: What is the final temperature when 63.4 g of water at 84.2 ° C is mixed with 38.5 g of water at…

A: Given : Mass of hot water = 63.4 g Mass of cold water = 38.5 g Temperature of hot water = 84.2 oC…

Q: What is the amount of heat (value of q) when 22.8 g of gold is heated from 20.0℃ to 425℃? The…

A: Specific Heat capacity: The amount of heat required to increase the temperature of one gram of a…

Q: The temperature of a sample of aluminum increased by 22.5 degrees celsius when 257 J of heat was…

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Q: 24.0 g of metal at 78.3°C is cooled to 12.4°C and produces 194 J of heat. What is the specific heat…

A: Mass of substance M = 24.0 g  Initial temperature = 78.3 °C  Final temperature = 12.4°C  Heat…

Q: mass

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Q: It takes 42.0 JJ to raise the temperature of an 9.40 gg piece of unknown metal from 13.0∘C∘C to 24.6…

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Q: When 4.3 kJ of heat are added to an unknown quantity of water, the temperature rises from 34oC to…

A: 4.3 KJ of heat is added to an unknown quantity of water and the temperature of water rises from…

Q: The specific heat for iron is 0.444 J/g Celsius . What is the final temperature of a 41.4 g sample…

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Q: A 10.0 gram lead ball was heated with 55.5 joules of heat to 50.0 oC. Given the specific heat of…

A: A 10.0 gram lead ball was heated with 55.5 joules of heat to 50.0 °C. Given the specific heat of…

Q: if 624J of heat is added to 30.2g of water at 24.3°c, what will the final temperature of the water…

A: The amount of heat added is = 624 J The initial temperature of the water is = 24.3oC The mass of…

Q: A piece of gold (specific heat of 0.129 J/g oC) at 190 oC is placed in 165 mL of water. The initial…

A: The heat lost by the piece of gold is absorbed by water. The amount of heat absorbed by water can be…

Q: A block of metal weighing 57.58 g is cooled from 100.0°C to 42.16°C with the release of 544.08…

A: Given, Mass of metal (mmetal) = 57.58 g Initial temperature (Ti) = 100°C Final temperature (Tf) =…

Q: What is the final temperature when a 5.0 g sample of brass initially at 25 oC absorbs 75 J of heat?…

A: Equation for finding the heat absorbed by brass is as follows. Q=mc∆TQ=heat absorbed by brassm=mass…

Q: How much heat must be added to a 8.21 g sample of gold to increase its temperature from 25 oC to…

A: We know that Q = m×C×∆T Q = heat m = mass C = Specific heat ∆T = change in temperature m = 8.21g C =…

Q: A 15.0 gram lead ball at 25.0°C was heated with 40.5 joules of heat. Given the specific heat of lead…

A: The change in temperature of the lead ball can be calculated by equation (1). where q is the heat…

Q: A 225-g sample of aluminum was heated to 125.5 oC, then placed into 500.0 g water at 22.5 oC. (The…

A: Here we have:           mass of aluminiun, mAl = 225 g             mass of water , mH2O = 500.0 g…

Q: A 35.0-g sample of water at 25°C is mixed with 45.0 g of water at 88°C. Calculate the final…

A: Calculate for the final temperature of the mixture see step-2 for further Calculation and concept…

Q: The amount of energy needed to heat 2.00 g mercury from 50.0°C to 85°C is 9.87 J. The specific heat…

A: Given: Mass of mercury=2.00 g Temperature change, ∆T=(85-50.0)°C=35 °C Heat needed q =9.87 J…

Q: What is the specific heat capacity of a piece of wood if 3500. g of the wood absorbs 47,550. joules…

A: From the formula of specific heat capacity we have solved this problem.

Q: A sample of water with a mass of 46.30 g absorbs 3.800 kJ of heat energy. If the initial temperature…

A: Given the mass of water =46.30 g heat absorbed by water =3.800 kJ =3800 J initial temperature of…

Q: It takes 55.0 JJ to raise the temperature of an 9.60 gg piece of unknown metal from 13.0∘C∘C to 24.4…

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Q: What is the specific heat of a 72.01 g piece of an unknown metal that exhibits a 45.2°C temperature…

A: Given data is  mass of sample = 72.01 g Temperature = 45.2 oC Heat absorbed = 1870 J Formula used…

Q: A 135 g sample of metal requires 2.50 kJ to change its temperature from 19.5 oC to 100.0 oC. What is…

A: Given,Mass of the metal, m = 135 gHeat required, q =2.50 kJ = 2500 J    (1 kJ = 1000 J)Initial…

Q: A sample of unknown metal had a mass of 120.4g. As the sample cools from 90.5 degrees C to 25.7…

A: Given, mass of metal = 120.4 g Initial Temperature = 90.5°C  Final temperature = 25.7°C  Specific…

Q: 6.00 J of heat is added to 10.00 g of gold, which is initially at 25°C The heat capacity of gold is…

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Q: How many joules of heat must be removed from 432g of water. (heat capacity of 4.184j / g celsuis) to…

A: Joules of heat can be calculated by using following formula,The equation for heat is  Q=m(Δt)Cp

Q: what quantity of heat energy must have been applied to a block of aluminum weighing 38.4g of the…

A: The total heat required (Q) is determined as follows. Q=mAlcAl∆T ...... (1)

Q: Calculate the heat capacity for 50.0 g of water in units of J/oC and calories/oC.

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Q: A 100.0g sample of water at 25.30 degrees Celsius was placed in an insulated cup. Then 45.00g of…

A: Given that: Mass of water = 100.0 g Initial temperature of water = 25.30°C Mass of lead pellets =…

Q: a 25.31 g sample of a substance is initially at 23.9 °c. after absorbing 2317 j of heat, the…

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