A Biology professor is teaching sections A and B of BIOL1000. The professor knows from thepast that the student exam marks of section A follows a normal distribution with an average of65, and a standard deviation of 10 while the student's exam marks of section B follows a normaldistribution with an average of 70, and a standard deviation of 20.a) Find the probability that the average exam marks by a random sample of 100 students insection B is less than 67.b) What is the probability that the average exam marks of 81 randomly selected studentsfrom section A is one mark higher than the average exam marks of 100 randomlyselected students from section B?c) The professor declares that no more than one-quarter of section B’s students will getaverage marks. What is the probability that in a random sample of the 80 section Bstudents, more than 28 will get the average marks?d) (Solve this part independently). A random sample of 6 National bank employees was taken tohelp estimate the average amount of time(x) employees spent per week on their cell phones. Thesample data and some relevant information are listed below:13, 5, 6, 10, 7, 12.Ex = 53, Sample Variance of x = 10.9667Find an unbiased estimator of the average time per week for all bank employees.

Given information:- μA=65σA=10μB=70σB=20 As per guidelines we will only answer the first three…

Answered: A Biology professor is teaching…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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