A biologist looked at the relationship between number of seeds a plant produces and the percent of those seeds that sprout. The results of the survey are shown below. Seeds Produced 42 59 58 50 69 69 56 Sprout Percent 79.2 71.4 56.8 76 52.4 51.4 70.6 a. Find the correlation coefficient: r = 0.89 Round to 2 decimal places. b. The null and alternative hypotheses for correlation are: Ho: P v = 0 Η: ν The p-value is: 0.0073 (Round to four decimal places) c. Use a level of significance of a = 0.05 to state the conclusion of the hypothesis test in the context of the study. O There is statistically significant evidence to conclude that a plant that produces more seeds will have seeds with a lower sprout rate than a plant that produces fewer seeds. O There is statistically insignificant evidence to conclude that a plant that produces more seeds will have seeds with a lower sprout rate than a plant that produces fewer seeds. O There is statistically significant evidence to conclude that there is a correlation between the number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the regression line is useful. O There is statistically insignificant evidence to conclude that there is a correlation between the number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the use of the regression line is not appropriate. d. r = 0.79 (Round to two decimal places) e. Interpret r2 : O There is a 81% chance that the regression line will be a good predictor for the percent of seeds that sprout based on the number of seeds produced. O Given any group of plants that all produce the same number of seeds, 81% of all of these plants will produce seeds with the same chance of sprouting. O 81% of all plants produce seeds whose chance of sprouting is the average chance of sprouting. O There is a large variation in the percent of seeds that sprout, but if you only look at plants that produce a fixed number of seeds, this variation on average is reduced by 81%. f. The equation of the linear regression line is: ŷ = (Please show your answers to two decimal places) g. Use the model to predict the percent of seeds that sprout if the plant produces 55 seeds. Percent sprouting = (Please round your answer to the nearest whole number.) h. Interpret the slope of the regression line in the context of the question: O The slope has no practical meaning since it makes no sense to look at the percent of the seeds that sprout since you cannot have a negative number. O For every additional seed that a plant produces, the chance for each of the seeds to sprout tends to decrease by 1.07 percent. O As x goes up, y goes down. i. Interpret the y-intercept in the context of the question: O The y-intercept has no practical meaning for this study.

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plz help me with question F and G

A biologist looked at the relationship between number of seeds a plant produces and the percent of those
seeds that sprout. The results of the survey are shown below.
cements
Seeds Produced
59
58 50
42
69
69
56
Sprout Percent
79.2 71.4
56.8 76 52.4 51.4
70.6
a. Find the correlation coefficient: r = 0.89
Round to 2 decimal places.
b. The null and alternative hypotheses for correlation are:
Ho: P V = o
H1: p V + 0
The p-value is: 0.0073 (Round to four decimal places)
55
xam Proctor
c. Use a level of significance of a = 0.05 to state the conclusion of the hypothesis test in the context
of the study.
O There is statistically significant evidence to conclude that a plant that produces more seeds
will have seeds with a lower sprout rate than a plant that produces fewer seeds.
O There is statistically insignificant evidence to conclude that a plant that produces more seeds
will have seeds with a lower sprout rate than a plant that produces fewer seeds.
tion
O There is statistically significant evidence to conclude that there is a correlation between the
number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the
regression line is useful.
le
tebook
O There is statistically insignificant evidence to conclude that there is a correlation between the
number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the use
of the regression line is not appropriate.
Forms
d. r2 - 0.79
(Round to two decimal places)
=
e. Interpret r2 :
t Teams
O There is a 81% chance that the regression line will be a good predictor for the percent of seeds
that sprout based on the number of seeds produced.
O Given any group of plants that all produce the same number of seeds, 81% of all of these
plants will produce seeds with the same chance of sprouting.
O 81% of all plants produce seeds whose chance of sprouting is the average chance of sprouting.
O There is a large variation in the percent of seeds that sprout, but if you only look at plants
that produce a fixed number of seeds, this variation on average is reduced by 81%.
f. The equation of the linear regression line is:
* (Please show your answers to two decimal places)
g. Use the model to predict the percent of seeds that sprout if the plant produces 55 seeds.
Percent sprouting =
(Please round your answer to the nearest whole number.)
h. Interpret the slope of the regression line in the context of the question:
O The slope has no practical meaning since it makes no sense to look at the percent of the seeds
that sprout since you cannot have a negative number.
O For every additional seed that a plant produces, the chance for each of the seeds to sprout
tends to decrease by 1.07 percent.
O As x goes up, y goes down.
i. Interpret the y-intercept in the context of the question:
O The y-intercept has no practical meaning for this study.
O The average sprouting percent is predicted to be 127.17.
Olf plant produces no seeds, then that plant's sprout rate will be 127.17.
O The best prediction for a plant that has 0 seeds is 127.17 percent.
Transcribed Image Text:A biologist looked at the relationship between number of seeds a plant produces and the percent of those seeds that sprout. The results of the survey are shown below. cements Seeds Produced 59 58 50 42 69 69 56 Sprout Percent 79.2 71.4 56.8 76 52.4 51.4 70.6 a. Find the correlation coefficient: r = 0.89 Round to 2 decimal places. b. The null and alternative hypotheses for correlation are: Ho: P V = o H1: p V + 0 The p-value is: 0.0073 (Round to four decimal places) 55 xam Proctor c. Use a level of significance of a = 0.05 to state the conclusion of the hypothesis test in the context of the study. O There is statistically significant evidence to conclude that a plant that produces more seeds will have seeds with a lower sprout rate than a plant that produces fewer seeds. O There is statistically insignificant evidence to conclude that a plant that produces more seeds will have seeds with a lower sprout rate than a plant that produces fewer seeds. tion O There is statistically significant evidence to conclude that there is a correlation between the number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the regression line is useful. le tebook O There is statistically insignificant evidence to conclude that there is a correlation between the number of seeds that a plant produces and the percent of the seeds that sprout. Thus, the use of the regression line is not appropriate. Forms d. r2 - 0.79 (Round to two decimal places) = e. Interpret r2 : t Teams O There is a 81% chance that the regression line will be a good predictor for the percent of seeds that sprout based on the number of seeds produced. O Given any group of plants that all produce the same number of seeds, 81% of all of these plants will produce seeds with the same chance of sprouting. O 81% of all plants produce seeds whose chance of sprouting is the average chance of sprouting. O There is a large variation in the percent of seeds that sprout, but if you only look at plants that produce a fixed number of seeds, this variation on average is reduced by 81%. f. The equation of the linear regression line is: * (Please show your answers to two decimal places) g. Use the model to predict the percent of seeds that sprout if the plant produces 55 seeds. Percent sprouting = (Please round your answer to the nearest whole number.) h. Interpret the slope of the regression line in the context of the question: O The slope has no practical meaning since it makes no sense to look at the percent of the seeds that sprout since you cannot have a negative number. O For every additional seed that a plant produces, the chance for each of the seeds to sprout tends to decrease by 1.07 percent. O As x goes up, y goes down. i. Interpret the y-intercept in the context of the question: O The y-intercept has no practical meaning for this study. O The average sprouting percent is predicted to be 127.17. Olf plant produces no seeds, then that plant's sprout rate will be 127.17. O The best prediction for a plant that has 0 seeds is 127.17 percent.
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