A biologist is attempting to determine the mean weight of African elephants. She conducts a sample of 60 elephants, and finds a sample mean of 8954 lbs., with a standard deviation of 127 lbs. Assume that the distribution of weights of African elephants is nearly normal.Define your variable:Let μμ be the mean weight of all African elephants, in lbs..Let μμ be the mean weight of the sampled African elephants, in lbs..Let p be the proportion of elephants that weigh .Let p be the proprotion of elephants in the sample.Create and interpret a 95% Confidence Interval. Round your answers to one decimal place. and lbs.What is the margin of error? Round your answer to one decimal place. lbs.Another biologist believes that the mean weight of elephants is 89898989. What do you think of this claim?That claim is not in our interval. We do not believe it.The claim is above the sample mean, so there is no way it can be true.The claim is inside the interval. It is reasonable.The claim is inside the interval. It must be true.

The random variable weight of African elephants follows normal distribution. The sample size is 60. The sample mean is 8954 lbs. The standard deviation is 127 lbs. We have to construct 95% Confidence Interval for the population mean.Let μ be the mean weight of all African elephants, in lbs.. Df = n-1 = 60-1 = 59. From T-distribution table, the critical value at 59 df and 95% level is 2.001. Thus the 95% Confidence Interval is 8921.2 lbs and 8986.8 lbs.Interpretation: One can be 95% confident that the population mean weight of all African elephants falls between the confidence limits. Margin of error = 32.8 lbs. That claim is not in our interval. We do not believe it.

Answered: A biologist is attempting to determine…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A biologist is attempting to determine the mean weight of African elephants. She conducts a sample of 60 elephants, and finds a sample mean of 8954 lbs., with a standard deviation of 127 lbs. Assume that the distribution of weights of African elephants is nearly normal.

Define your variable:

Let μμ be the mean weight of all African elephants, in lbs..
Let μμ be the mean weight of the sampled African elephants, in lbs..
Let p be the proportion of elephants that weigh .
Let p be the proprotion of elephants in the sample.

Create and interpret a 95% Confidence Interval. Round your answers to one decimal place. and lbs.

What is the margin of error? Round your answer to one decimal place. lbs.

Another biologist believes that the mean weight of elephants is 89898989. What do you think of this claim?

That claim is not in our interval. We do not believe it.
The claim is above the sample mean, so there is no way it can be true.
The claim is inside the interval. It is reasonable.
The claim is inside the interval. It must be true.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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