A binary star consist of two stars of the same mass m revolving in a circle of radius R about theircommon centre of mass. Suppose that a meteorite passes through the centre of mass of the binarystar in a direction perpendicular to the orbital plane. What is the minimum speed that the meteoritemust have at the centre of mass in order for it to escape from the gravitational attraction of thebinary star?ANSW:4GmRw

The objective of this question is to find the minimum speed that a meteorite must have at the centre…

Answered: A binary star consist of two stars of…

Similar questions

5. A space vehicle is traveling at 4300 km/h relative to Earth when the exhausted rocket motor (mass 4m) is disengaged and sent backward with a speed of 82 km/h relative to the command module (mass m). What is the speed of the command module relative to Earth just after the separation? f mass
The perihelion of the comet TOTAS is 1.69 AU and the aphelion is 4.40 AU. Given that its speed at perihelion is 28 km/s, what is the speed (in km/s) at aphelion (1 AU = 1.496 x 1011 m)? (Hint: You may use either conservation of energy or angular momentum, but the latter is much easier.) |km/s Additional Materials O eBook
question C
Center of Mass. c) The mass of the Sun is 2x1030 kg. The distance between the Earth and the Sun is 1.5x108 km. How does the distance between the CM of this system compare to the Sun’s radius of 700,000 km?
9 pl
Problem B) The mass of the Earth is 5.97 x 1024 kg and the mass of the Sun is 1.99 x 1030 kg. The average distance between the Sun and the Earth is 1.5 x 1011 m from their centers. Where is the center of mass of the Earth-Sun system located with respect to the center of the Sun? If the radius of the Sun is 6.96 x 108 m, is the center of mass within the Sun or outside the Sun?
A satellite is in a circular orbit of radius r around the Earth. (Use the following as necessary: G, ME, and r.) a) Determine an expression that will allow you to find the speed of the satellite. b)The satellite splits into two fragments, with masses m and 4m. The fragment with mass m is initially at rest with respect to the Earth, then falls straight towards the Earth. The fragment with mass 4m moves with initial speed vi. Find an expression for vi. c)Because of the increase in its speed, this larger fragment now moves in an elliptical orbit. Find an expression for the fragment's distance away from the center of the Earth when it reaches the far end of the ellipse.
How to solve?
What is the linear momentum of a 74.0 kg object on the Equator, as measured from the center of Earth? The radius R of Earth is 6371 km.
e A spaceship of mass m travels from the Earthto the Moon along a line that passes through the center of theEarth and the center of the Moon. (a) At what distance from thecenter of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon? (b) How does your answer topart (a) depend on the mass of the spaceship? Explain
Fnnjjkj
Do them alll

SEE MORE QUESTIONS