A binary search is to be performed on the list, S = [6, 2, 5, 7, 9, 12, 1, 10, 8, 4] How many comparisons would it take to find number 10, worst case?
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- Consider the following list: int list[] = (14, 18, 29, 35, 44, 49, 55, 58, 66, 71, 75, 80, 89, 95, 98) %3D When performing a binary search for 75, after the first comparison, the search is restricted to O list[8].. .list[14] O list [5]...list[11] O list[0].. .list[7] O list [0]. . .list[6]True or false? The best-case number of comparisons needed to conduct a linear search of an array of n integers is n. True FalseGiven a list (69, 97, 34, 58, 92, 94, 64, 88, 63, 44) and a gap value of 4: What is the list after shell sort with a gap value of 4?
- For a linear search, put the following code in the correct order by dragging each line to the correct place. 2 3 4 5 for (int i = 0; i < list.length; i++) { if (key == list[i]) return i; } } return -1; public static int linearSearch(int[] list, int key) {12. Find By Value Runtimes What is the worst case runtime for a "find by value" operation for linked lists and for balanced binary search trees? Pick ONE option Linked List: 0(n^2); Balanced BST: O(1) Linked List: 0(n); Balanced BST: O(log(n)) Linked List: O(n^2) ; Balanced BST: O(log(n)) Linked List: 0(n) ; Balanced BST: O(n)Let A be an array, where each of the n elements is a randomly chosen digit between 0 and 9. For example, if n = 12, this array could be A = [3,5,1,0,5,7,9,2,2,8,8,6]. Determine whether Counting Sort or Merge Sort sorts this array faster.
- How many iterations are needed untill we find 75 in this listTrace counting sort on the following list L of unordered keys which lie withinthe range [10, 18].L[1:10]: 16 11 18 13 11 12 15 15 18 16The bubble sort algorithm shown in this chapter is less efficientthan it could be. If a pass is made through the list without exchanging any elements, this means that the list is sorted and thereis no reason to continue. Modify this algorithm so that it willstop as soon as it recognizes that the list is sorted. Do not use abreak statement