A = - bh 9. Solve for b.

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem 9: Algebraic Manipulation

**Solve the equation**  
\[ A = \frac{1}{2} bh \]  
**for \( b \).**

**Choose the correct option:**

- **Option A:**  
  \[ b = \frac{2h}{A} \]

- **Option B:**  
  \[ b = \frac{2A}{h} \]

- **Option C:**  
  \[ b = \frac{A}{2h} \]

- **Option D:**  
  \[ b = \frac{h}{2A} \]

**Explanation:**

To solve the equation \( A = \frac{1}{2} bh \) for \( b \), you need to manipulate the equation to isolate \( b \) on one side:

1. Begin by multiplying both sides of the equation by 2 to get rid of the fraction:
   \[ 2A = bh \]

2. Divide both sides by \( h \) to solve for \( b \):
   \[ b = \frac{2A}{h} \]

The correct answer is **Option B:**  
\[ b = \frac{2A}{h} \]

---
Transcribed Image Text:Sure, here's a transcription and explanation for an educational website: --- ### Problem 9: Algebraic Manipulation **Solve the equation** \[ A = \frac{1}{2} bh \] **for \( b \).** **Choose the correct option:** - **Option A:** \[ b = \frac{2h}{A} \] - **Option B:** \[ b = \frac{2A}{h} \] - **Option C:** \[ b = \frac{A}{2h} \] - **Option D:** \[ b = \frac{h}{2A} \] **Explanation:** To solve the equation \( A = \frac{1}{2} bh \) for \( b \), you need to manipulate the equation to isolate \( b \) on one side: 1. Begin by multiplying both sides of the equation by 2 to get rid of the fraction: \[ 2A = bh \] 2. Divide both sides by \( h \) to solve for \( b \): \[ b = \frac{2A}{h} \] The correct answer is **Option B:** \[ b = \frac{2A}{h} \] ---
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