A bent rod has a diameter of d=15 mm and is subjected to a force of P= 600 N. What is the normal stress developed at point A?* (2 Points) -120 mm A -120 mm- P 60 mm B

Q: A bar of length 3 m is fixed at both the ends as shown in figure initial stress in bar is 30 MPa…

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Q: e average normal stress

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Q: Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Take di = 30 mm,…

A: Determine the average normal stress at the midsection of rod BC.

Q: The rod has a diameter of 40 mm. Determine the state of stress at point A and draw the resulting 3-D…

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Q: For the stress block shown, what is OP2 if OP1 = 140 MPa (T)? A.60 MPa (T) 40 MPa B.60 MPa (C) C.20…

A: Calculations:σx=+120mpaσy=-40Mpaσ1=140mpagivenσ1=σx+σy2+σx-σy2+ζxy2140=120-402+120+4022+ζxy2140=40+8…

Q: ! Required information Consider the given state of stress. Take A= 16 MPa and B= 55 MPa. B 60 MPa…

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Q: Knowing that the machine component shown has a trapezoidal cross section with a = 2.5 in. and b =…

A: A trapezoidal section is given on which a moment of magnitude M = 75 kip-in is applied, To…

Q: Q.2) A rigid bar ACD is supported by two circular steel (E= 30x10° psi) rods DE and a pin support at…

A: Draw free body diagram From deflected shape δAB8=δP4=δDE6=tanθ Consider the moment equilibrium…

Q: 1) The copper pipe below has an outer diameter of 50 mm, inner diameter of 30 mm, and G = 45 GPa. It…

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Q: A circular steel tube of length L = 1.5 m is loaded in torsion by torques T (see figure). (a) If the…

A: INTRODUCTION: This is the case of circular section for twist to be applied which causes the shear…

Q: mine the maximum shear stress for the 7.. 3₁ == 0 MPa Txy=-31 Ox=37

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Q: The column is subjected to an axial force of 8 kN, which is applied through the centroid of the…

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Q: The member is loaded as shown. The diameter of the member is 32 mm. 1) Calculate all internal…

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Q: The d - 16-mm-diameter solid rod passes through a D=21-mm-diameter hole in the support plate. When a…

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Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.