Please help in 4 part question thanks A bearing used in an automotive application is required to have a nominal inside diameter of 1.5 inches. A random sample of 25 bearings is selected, and the average inside diameter of these bearings is 1.4975 inches. Bearing diameter is known to be normally distributed with a standard deviation of \( \sigma = 0.01 \) inch.**(a)** Test the hypotheses \( H_0: \mu = 1.5 \) versus \( H_1: \mu \neq 1.5 \) using \( \alpha = 0.01 \).The true mean hole diameter [Dropdown Box: Insert Calculation] significantly different from 1.5 in. at \( \alpha = 0.01 \).**(b)** What is the P-value for the test in part (a)?P-value = [Input Box: Insert Calculation] Round your answer to two decimal places (e.g., 98.76).**(c)** Compute the power of the test if the true mean diameter is 1.495 inches.Power of the test = [Input Box: Insert Calculation] Round your answer to two decimal places (e.g., 98.76).**(d)** What sample size would be required to detect a true mean diameter as low as 1.495 inches if we wanted the power of the test to be at least 0.90?[Input Box: Insert Calculation] bearings.This educational resource includes tools for performing hypothesis testing and power analysis for normally distributed data with provided sample mean, standard deviation, and significance level.

Given n=25 Alpha=0.01 X-bar=1.4975

A bearing used in an automotive application is required to have a nominal inside diameter of 1.5 inches. A random sample of 25 bearings is selected and the average inside diameter of these bearings is 1.4975 inches. Bearing diameter is known to be normally distributed with standard deviation o = 0.01 inch. (a) Test the hypotheses Ho: μ = 1.5 versus H₁ : μ The true mean hole diameter (b) What is the P-value for the test in part (a)? P-value = i 1.5 using a = 0.01. significantly different from 1.5 in. at a = 0.01. (c) Compute the power of the test if the true mean diameter is 1.495 inches. Power of the test = i Round your answer to two decimal places (e.g. 98.76). bearings (d) What sample size would be required to detect a true mean diameter as low as 1.495 inches if we wanted the power of the test to be at least 0.90? Round your answer to two decimal places (e.g. 98.76). Statistical Tables and Charts

A bearing used in an automotive application is required to have a nominal inside diameter of 1.5 inches. A random sample of 25 bearings is selected and the average inside diameter of these bearings is 1.4975 inches. Bearing diameter is known to be normally distributed with standard deviation o = 0.01 inch. (a) Test the hypotheses Ho: μ = 1.5 versus H₁ : μ The true mean hole diameter (b) What is the P-value for the test in part (a)? P-value = i 1.5 using a = 0.01. significantly different from 1.5 in. at a = 0.01. (c) Compute the power of the test if the true mean diameter is 1.495 inches. Power of the test = i Round your answer to two decimal places (e.g. 98.76). bearings (d) What sample size would be required to detect a true mean diameter as low as 1.495 inches if we wanted the power of the test to be at least 0.90? Round your answer to two decimal places (e.g. 98.76). Statistical Tables and Charts

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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