A bearing plate is to be designed for a W21x62, A36 steel beam that will sit on a reinforced concrete wall (f'c = 21 MPa) 200 mm thick. The bearing plate material has Fy = 345 MPa. The end reactions are a service dead load of 150 kN and live load of 300 kN. Determine the following using ASD: 1. Required minimum width and thickness of the bearing plate calculated assuming it is positioned at the center of the concrete wall. Use length N = 150 mm. B = [B] mm. Round up
A bearing plate is to be designed for a W21x62, A36 steel beam that will sit on a reinforced concrete wall (f'c = 21 MPa) 200 mm thick. The bearing plate material has Fy = 345 MPa. The end reactions are a service dead load of 150 kN and live load of 300 kN. Determine the following using ASD: 1. Required minimum width and thickness of the bearing plate calculated assuming it is positioned at the center of the concrete wall. Use length N = 150 mm. B = [B] mm. Round up
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Bearing Plate Design for A W21x62, A36 Steel Beam**
**Description:**
A bearing plate is to be designed for a W21x62, A36 steel beam that will sit on a reinforced concrete wall (f'c = 21 MPa) 200 mm thick. The bearing plate material has Fy = 345 MPa. The end reactions are a service dead load of 150 kN and a live load of 300 kN.
**Objective:**
Determine the following using ASD (Allowable Stress Design):
1. **Minimum Width and Thickness of the Bearing Plate:**
- Assumption: The plate is positioned at the center of the concrete wall.
- Use length N = 150 mm.
- Calculate B = [B] mm. Round up by 10 mm or 25 mm.
2. **Required Thickness of the Bearing Plate:**
- Given B = 300 mm, N = 200 mm.
- Compute t = [t] mm. Round up to the nearest whole number.
**Note:**
Replace placeholders [B] and [t] with calculated values as per the design requirements.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef49af5c-9039-416f-bcaa-34814d7a1303%2Fe52ba2d0-3e5a-4e23-b729-b6e83fcedeeb%2Fk8hfz6h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Bearing Plate Design for A W21x62, A36 Steel Beam**
**Description:**
A bearing plate is to be designed for a W21x62, A36 steel beam that will sit on a reinforced concrete wall (f'c = 21 MPa) 200 mm thick. The bearing plate material has Fy = 345 MPa. The end reactions are a service dead load of 150 kN and a live load of 300 kN.
**Objective:**
Determine the following using ASD (Allowable Stress Design):
1. **Minimum Width and Thickness of the Bearing Plate:**
- Assumption: The plate is positioned at the center of the concrete wall.
- Use length N = 150 mm.
- Calculate B = [B] mm. Round up by 10 mm or 25 mm.
2. **Required Thickness of the Bearing Plate:**
- Given B = 300 mm, N = 200 mm.
- Compute t = [t] mm. Round up to the nearest whole number.
**Note:**
Replace placeholders [B] and [t] with calculated values as per the design requirements.
Expert Solution
Step 1: Given data:-
The steel section used as bearing plate = W21format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22math13b8a614226a953a8cd9526fca6%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%227.5%22%20y%3D%2216%22%3E%26%23xD7%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
62
The yield strength of steel (fy) = 345 MPa
The strength of concrete (f'c) = 21 MPa
The magnitude of the dead load = 150 kN
The magnitude of the live load = 300 kN
To determine:-
a) The required minimum width and thickness of the bearing plate if N = 150 mm
b) The required thickness of the bearing plate if B = 300 mm, N = 200 mm
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