A beam sits on simple supports and has uniform loads.Transverse reinforcement consists of two legs of #3bars.1= 30 ftb = 16 ind = 30 inf = 5 ksify = 60 ksiWa = 2 k/ft (Includes the beam's weight)%3DW = 3 k/fta. Determine the practical spacing, s (in), oftransverse reinforcement necessary in the vicinityof the supports.b. At what distance x (in) on the beam's lengthfrom the left (and right) is a spacing of 12 inacceptable?

Solution:- Shear force in the section, Vu=wu×L2 Load calculation, wd=2×1.5 =3 k/ftwl =3×1.5 =4.5…

A beam sits on simple supports and has uniform loads. Transverse reinforcement consists of two legs of #3 bars. 1= 30 ft b = 16 in d = 30 in fe = 5 ksi fy = 60 ksi Wa = 2 k/ft (Includes the beam's weight) W =3 k/ft a. Determine the practical spacing,s (in), of transverse reinforcement necessary in the vicinity of the supports.

A beam sits on simple supports and has uniform loads. Transverse reinforcement consists of two legs of #3 bars. 1= 30 ft b = 16 in d = 30 in fe = 5 ksi fy = 60 ksi Wa = 2 k/ft (Includes the beam's weight) W =3 k/ft a. Determine the practical spacing,s (in), of transverse reinforcement necessary in the vicinity of the supports.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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