A beam of mass M and length ofL is in equilibrium as in the figure. If F = 70 N and M= 50 kg, (a) Draw all the forces acting on the beam. (b) Write the translational and rotational equilibrium equations and simplify them. Now take F = 70 N and M = 50 kg and calculate (c) The tension in the rope, and (d) The force from the ground on the beam.
A beam of mass M and length ofL is in equilibrium as in the figure. If F = 70 N and M= 50 kg, (a) Draw all the forces acting on the beam. (b) Write the translational and rotational equilibrium equations and simplify them. Now take F = 70 N and M = 50 kg and calculate (c) The tension in the rope, and (d) The force from the ground on the beam.
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![### Problem Statement
A beam of mass \( M \) and length of \( L \) is in equilibrium as shown in the figure. Given \( F = 70 \, \text{N} \) and \( M = 50 \, \text{kg} \), complete the following tasks:
#### (a) Draw all the forces acting on the beam.
#### (b) Write the translational and rotational equilibrium equations and simplify them.
#### (c) Calculate the tension in the rope.
#### (d) Calculate the force from the ground on the beam.
### Explanation of the Diagram
- The figure depicts a beam at an angle of \( 50^\circ \) with the horizontal ground.
- The beam is labeled with length \( L \) and a mass \( M \) that acts downward due to gravity.
- A force \( F \) is applied at an angle of \( 70^\circ \) from the beam.
- The ground exerts a normal force vertically upward, which is not explicitly shown, and possibly a horizontal force if friction is considered.
### Steps for Solution
#### (a) Drawing Forces on the Beam
1. Gravitational Force (\( Mg \)): Acts downward from the center of mass of the beam.
2. Force \( F \): Acts outward at an angle of \( 70^\circ \) from the beam.
3. Tension in the Rope (\( T \)): Acts along the rope.
4. Normal Force (\( N \)): Acts perpendicular to the surface of contact between the beam and the ground.
5. Friction Force (if any, \( f \)): Acts parallel to the ground at the point of contact.
#### (b) Translational and Rotational Equilibrium Equations
- **Translational Equilibrium**:
\[
\sum F_x = 0 \quad \text{and} \quad \sum F_y = 0
\]
- **Rotational Equilibrium**:
\[
\sum \tau = 0
\]
where \(\tau\) is the torque about any point (often taken as the point of contact with the ground for simplicity).
#### (c) Calculate the Tension in the Rope
Using the given values for \( F \) and \( M \):
\[
F = 70 \, \text{N}
\]
\[
M = 50 \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb397ef84-6eeb-40b9-aea4-22211e922ea0%2F81eac117-c435-42bf-94aa-bf1914c7b81e%2F1ro3kdc_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A beam of mass \( M \) and length of \( L \) is in equilibrium as shown in the figure. Given \( F = 70 \, \text{N} \) and \( M = 50 \, \text{kg} \), complete the following tasks:
#### (a) Draw all the forces acting on the beam.
#### (b) Write the translational and rotational equilibrium equations and simplify them.
#### (c) Calculate the tension in the rope.
#### (d) Calculate the force from the ground on the beam.
### Explanation of the Diagram
- The figure depicts a beam at an angle of \( 50^\circ \) with the horizontal ground.
- The beam is labeled with length \( L \) and a mass \( M \) that acts downward due to gravity.
- A force \( F \) is applied at an angle of \( 70^\circ \) from the beam.
- The ground exerts a normal force vertically upward, which is not explicitly shown, and possibly a horizontal force if friction is considered.
### Steps for Solution
#### (a) Drawing Forces on the Beam
1. Gravitational Force (\( Mg \)): Acts downward from the center of mass of the beam.
2. Force \( F \): Acts outward at an angle of \( 70^\circ \) from the beam.
3. Tension in the Rope (\( T \)): Acts along the rope.
4. Normal Force (\( N \)): Acts perpendicular to the surface of contact between the beam and the ground.
5. Friction Force (if any, \( f \)): Acts parallel to the ground at the point of contact.
#### (b) Translational and Rotational Equilibrium Equations
- **Translational Equilibrium**:
\[
\sum F_x = 0 \quad \text{and} \quad \sum F_y = 0
\]
- **Rotational Equilibrium**:
\[
\sum \tau = 0
\]
where \(\tau\) is the torque about any point (often taken as the point of contact with the ground for simplicity).
#### (c) Calculate the Tension in the Rope
Using the given values for \( F \) and \( M \):
\[
F = 70 \, \text{N}
\]
\[
M = 50 \
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