### Physics Problem: Beam and PivotA beam of length \( L \) and mass \( M \) rests on two pivots. The first pivot is at the left end, considered the origin, and the second pivot is at a distance \( \ell \) from the left end. A woman of mass \( m \) starts at the left end and walks toward the right end as shown in the figure below.#### Diagram ExplanationThe diagram shows a horizontal beam resting on two upward-pointing arrows representing the pivots. The beam has length \( L \), with its left end at the origin. The second pivot is located at distance \( \ell \) from the left end. A woman is walking on the beam, and her distance from the left end is marked as \( x \).#### Problems**(a)** When the beam is on the verge of tipping, find a symbolic expression for the normal force \( n_2 \) exerted by the second pivot in terms of \( M \), \( m \), and \( g \).\[ n_2 = \underline{\hspace{3cm}} \]**(b)** When the beam is on the verge of tipping, find a symbolic expression for the woman's position \( x \) in terms of \( M \), \( m \), \( L \), and \( \ell \).\[ x = \underline{\hspace{3cm}} \]**(c)** Find the minimum value of \( \ell \) that will allow the woman to reach the end of the beam without it tipping. (Use any variable or symbol stated above as necessary.)\[ \ell_{\text{min}} = \underline{\hspace{3cm}} \]

Answered: Image /qna-images/answer/adea2a62-9126-43b5-8226-f1f3b8c7dfcc.jpg

A beam of length L and mass M rests on two pivots. The first pivot is at the left end, taken as the origin, and the second pivot is at a distance e from the left end. A woman of mass m starts at the left end and walks toward the right end as in the figure below. (a) When the beam is on the verge of tipping, find symbolic expression for the normal force exerted by the second pivot in terms of M, m, and g. n2 = (b) When the beam is on the verge of tipping, find symbolic expression for the woman's position in terms of M, m, L, and f. (c) Find the minimum value of e that will allow the woman to reach the end of the beam without it tipping. (Use any variable or symbol stated above as necessary.) min =

A beam of length L and mass M rests on two pivots. The first pivot is at the left end, taken as the origin, and the second pivot is at a distance e from the left end. A woman of mass m starts at the left end and walks toward the right end as in the figure below. (a) When the beam is on the verge of tipping, find symbolic expression for the normal force exerted by the second pivot in terms of M, m, and g. n2 = (b) When the beam is on the verge of tipping, find symbolic expression for the woman's position in terms of M, m, L, and f. (c) Find the minimum value of e that will allow the woman to reach the end of the beam without it tipping. (Use any variable or symbol stated above as necessary.) min =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q3:-The mechanism in figure, determine the scalar component Pt and Pn which are tangent and normal respectively to crank BC
The AB arm shown in the figure can be rotated from point A by a motor. L = 0.6 m, spring coefficient k = 500 N / m and the length of the spring without extension (unloaded) 0.65 m is given. Which of the following is the value of the moment M (in N.m) applied by the motor at the position θ = 30 ° of the AB arm?
A uniform beam of length L = 13.6 meters and mass of 115.1 kg is pinned at one end and is being supported by awire as shown. The wire is connected to the beam x = 4.4 meters from the pin. A person of mass 98.3 kg is standingall the way out on the edge of the beam, the tension in the wire is 4624 N, θ = 16.2 degrees, and φ = 78.9 degrees.If the positive x-axis points to the right, find the horizontal component of the force from the pin on the beam.(in N) a. 1463 b. 2121 c. 3075 d. 4459 e. 6466
7. A person holds a m kg ball in his hand. The forearm is horizontal, as shown in Figure. The biceps muscle is attached d cm from the elbow joint, and the ball is 1 cm from the elbow joint. Find the upward force exerted by the biceps on the forearm and the downward force exerted by the upper arm on the forearm and acting at the joint. (d = 4 cm, l = 40 cm and M = 10 kg, m = 2 kg, 0 = 15) d cm Bone Muscle 1 cm
The specialty wrench shown in the figure is designed for access to the hold-down bolt on certain automobile distributors. For the configuration shown, where the wrench lies in a vertical plane and a horizontal 290-N force F is applied at A perpendicular to the handle, calculate the moment Mo applied to the bolt at O. For what value of the distance d would the z-component of Mo be zero? Assume a = 85 mm, d = 155 mm, h = 150 mm, 0 = 28° F Answers Mo = ( i d = i 0 h i+ i mm j+ i k) N.m
Two street lights are mounted as shown in the figure one at A and the other at C. The member AD is able to freely rotate about D. Member BE is a steel cable. B. EACH street light has a mass of 5 kg, AB=20cm, BC=20cm, CD=10cm, DE=17.32cm. Assume gravity is 9.81 N/kg. h=4cm Draw the shear force profile (a) between point A and D. On the diagram, clear indicate the values on the diagram. (b) member just to the right of point B. Calculate the maximum bending shear stress. At what distance from the bottom does it occur? Consider a cross-section of the (c) distance from the bottom does the minimum bending shear stress occur? What is its value? For the same cross-section, at what
A board sits in equilibrium. On the left end, there is a wire that supports the board from the ceiling, and to the right, there is a sawhorse that supports the board from the ground. The sawhorse is a distance d= 1/5l from the right edge of the board. There is a block with mass ms= 4.5kg that is a distance 3/4l from the right edge of the board. Finally the board has a mass mb= 11kg. c) Write down Newton's 2nd law. Put the equation in terms of mb, ms, g, T, and Fn. Where T is the tension in the wire, and Fn is the normal force of the sawhorse on the board. d) Write down Newton's 2nd Law for rotations. Put the equation in terms of l, mb, ms, g, T, and Fn.
SECW OM A motorbike wheel with an 8 kg mass has a 0.4 m radius of gyration around the z-axis, as shown in Figure. The wheel's shaft is supported by bearings A and B and rotates at a constant rate of 150 rpm in a counter-clockwise direction from the z-axis, while the frame rotates at 12 rpm in a counter- clockwise direction from the y-axis. Determine the resultant reaction forces at each bearing A and B due to the mass and gyroscopic effects. With the result of forces, which bearing has a tendency to fail first, which bearing should be considered for design purposes and explain the effect on motor if the bearing fail. y 0.55 0.4 All dimensions in meter (m)
It is desired to balance the rotor shown in the figure by placing balancing masses at a distance of ei and Li mm from the rotation axis in the R and L balancing planes. Find the balancing masses and their angular positions to be used in balancing. in the tableUse the given values.Find the L and R support reactions.
Choose the mass M in the figure with a value that does not end with zero from 302 to 497 kg. Find the support responses A and B. Draw the cross-sectional influence diagrams of the beam and write the maximum and minimum values.
can you answer this question
3 Moment and Torque Vectors Problem 3.8 As illustrated in Fig, 336, consider a cantile- ver beam of 9 kg mass. The beam is fixed to the wall at point A and at point B. The length of the beam is /= 4 m. Point C is the center of gravity of the beam. The weight of W1 50 N is attached at the free end of the beam such that the distance between point B and the line of gravity of the weight is /= 35 cm. A force with magnitude F applied at the free end of the beam to keep the beam in place. The line of action of the force makes an angle ß= 35 with 180 N is the horizont al. Detemine the magnitude and direction of the net moment generaled about point A, Answer: Mc 54.1N(ccw). ned tha l is AL r the ns of Fig. 3.36 A ut.s. e s hw heda tree d Problem 3.9 C ler the