A battery with emf E and internal resistance r is first connectedto a resistor of resistance R1 = R, where R is greater than r.This resistor is then disconnected from the battery and replaced with aresistorof resistance R2 = 2R. Find the ratio of the power dissipated in the second resistor to the power dissipated in the first resistor.

A battery with emf E and internal resistance r is first connectedto a resistor of resistance R1 = R, where R is greater than r.This resistor is then disconnected from the battery and replaced with aresistorof resistance R2 = 2R. Find the ratio of the power dissipated in the second resistor to the power dissipated in the first resistor.

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Question

A battery with emf E and internal resistance r is first connected
to a resistor of resistance R1 = R, where R is greater than r.
This resistor is then disconnected from the battery and replaced with a
resistor
of resistance R2 = 2R. Find the ratio of the power dissipated
in the second resistor to the power dissipated in the first resistor.

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