A battery of e.m.f. 12V supplies a current of 5A for 2 minutes. How much energy is supplied in this time?

Q: Please answer in typing format solution

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Q: R1=202 LOV R23D300 R3=500 L2 R4=200 Porales

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Q: Number of electrons in 1 Coulomb charge is a) 6.25*1021 b) 6.25*1020 c) 6.25*1025 d) 6.25*1023

A: The solution is provided in the following section.

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Q: Find power supplied to all of the diodes. D2 Si D3 R1 D1 5002 2V GaAs R2 D4 V1 1k2 Si 7V

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A: Formula to calculate force due to charge is: F=K×q1×q2r2

Q: Plz answer correctly ....

A: Step 1:Step 2:

Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.