A battery of 12 V and internal resistance (1) is connected to a load resistor R= 20. The potential difference across the load resistor is 10 Volt. What is its internal resistance (in Ohmes)? O 08 O 04 O0.0 O 0.6 O 1.0
Q: Calculate the equivalent resistance across a and b and the current and voltage across the 92…
A: 9Ω (branch df) and 6Ω (branch de) are in parallel, give rise to 9×69+6=3.6Ω. This combination is in…
Q: The circuit to the right consists of a battery (Vo = 6.00 V) and five resistors (R₁ = 311 22, R₂ =…
A: Given Data: Voltage v0 = 6.00 V.Resistance 1 R1 = 311 Ω.Resistance 2 R2 = 582 Ω.Resistance 3 R3 =…
Q: Two 6V and 12V batteries, whose internal resistance is ignored, were connected to two resistors with…
A:
Q: The circuit below has three resistors. If the current exiting the battery is 0.50 A, what is the…
A: Given value--- I = 0.50 Amp . R1 = 2 Ohm. R2 = 3 Ohm . R3 = 2 ohm . We have to find--- Potential…
Q: In the circuit shown belowɛ = 76.0 V, R5 = 4.00 2, R3 = 2.00 n, R2 = 2.20 0, Is = 8.40 A, %3D 14 =…
A: Given: Voltage = 76 V resistance, R5 = 4 ohm resistance, R3 = 2 ohm resistance, R2 = 2.2 ohm Current…
Q: A 9-V battery is connected to two resistors in series with resistors of 5 2 and 10 Q2 respectively…
A:
Q: The resistors in the circuit below have the following values: R₁ = 7.20 £2, R2 = 7.00 £2, and R3 =…
A: a) The current through R3 = 1.06Ab) The power dissipated through R3 = 3.37WExplanation:Please see…
Q: A battery has an emf of 15.0 V. The terminal voltage of the battery is 11.4 V when it is delivering…
A:
Q: In the circuit shown below & = 83.0 V, R5 = 4.00, R3 = 2.00, R₂ = 2.20 , I5 = 9.30 A, I4 = 6.00 A,…
A: E= 83 V R5 = 4 ohm R3 = 2 ohm R2 = 2.20 ohm I5 = 9.30 A I4 = 6 A I1 = 12.1 A
Q: . Consider a battery that has potential difference V₁ = 1.5 V across its terminals when it is not…
A:
Q: Four resistors having resistances of 5 2, 102, 152, and 20 22 are connected in series across an…
A: Given: R1=5ohm R2=10ohm R3=15ohm R4=20ohm I=1.5A To find: V
Q: In the figure battery 1 has emf 81 = 26.0 V and internal resistance r₁ = 0.024 02 and battery 2 has…
A: Given: E1 = 26.0 V r1 =0.024Ω…
Q: The resistance equivalent is 1.43 ohms. Now a 12V battery is connected between points A and B. What…
A: Write the expression for the current according to Ohm’s law.
Q: In the circuit shown in the figure. R1 = 10 0. R2- 120, R3- 200, V1-1.0v, V2=7.0V, and the batteries…
A:
Q: A resistor with resistance 25.5 2 is connected to the terminals of a voltage source. (a) Calculate…
A: a. Current through resistance is I=VR=7.5 V25.5Ω=0.29 A
Q: A 9V battery with internal resistance of 0.50 is connected across a 30 and a 50 resistor. The…
A: Electric current
Q: If the unknown resistor, R, is 20 Q, what is the voltage drop across that resistor, R? 10 0 10Ω. 10…
A: Solution:Here R1, R2 are in series thus…
Q: Suppose two batteries, with unequal emfs of 2.00 V and 3.00 V, are connected as shown in the figure.…
A:
Q: Two resistors of equal resistance R are connected in parallel across a cell with emf V. What is the…
A: Given : Two resistors of equal resistance R are connected in parallel across a cell with emf V.
Q: A 9V battery with internal resistance of 0.50 is connected across a 3 Q and a 5 2 resistor. The…
A:
Q: R₁ w ww R₂ R3 R Four resistors, R1 = 335 2, R2 = 335 2, R3 = 815 Q2, R4 = 335 Q are connected to a…
A: From the circuit diagram, resistance R1 are connected in parallel then the equivalent resistance…
Q: A 20 V battery is connected to a resistor. Neglecting the internal resistance of the battery, the…
A:
Q: A 597×10−6 F597×10−6 F capacitor is discharged through a resistor, whereby its potential difference…
A:
Q: The battery voltage is V = 80.6 V. The resistances are R1 = 123 Ohms; R2 = 114 Ohms; R3 = 139 Ohms;…
A: Given data V=80.6 VR1=123 ΩR2=114 ΩR3=139 ΩR4=159 ΩR5=56 ΩR6=199Ω
Q: If 480 C pass through a 4.0-0 resistor in 10 min, what is the potential difference across the…
A:
Step by step
Solved in 2 steps
- (a) What is the terminal voltage (in V) of a large 1.90 V carbon-zinc dry cell used in a physics lab to supply 1.20 A to a circuit, if the cell's internal resistance is 0.200 Q? V (b) How much electrical power (in W) does the cell produce? W (c) What power (in W) goes to its load? WSee the above circuit diagram to answer the question. The battery voltage is V = 66.1 V; R1 = 126 Ohms; R2 = 122 Ohms; R3 = 190 Ohms; R4 = 71 Ohms; R5 = 198 Ohms; and R6 = 120 Ohms. How much current flows through resistor R3? 0.144 A 0.170 A 0.093 A 0.195 AIn the figure R1 = 140 2, R2 = R3 = 66.0 , R4 = 89.8 2, and the ideal battery has emf ɛ = 6.00 V. (a) What is the equivalent resistance? What is I in each resistor R RA R2
- A battery has an emf of 15.0 V. The terminal voltage of the battery is 11.0 V when it is delivering 22.0 W of power to an external load resistor R. (a) What is the value of R? Ω (b) What is the internal resistance of the battery? ΩA student connects two resistors with unknown resistance values in series, and notes that the equivalent resistance R the equivalent resistance to be Rp = 140 02. What are the resistances (in 2) of each resistor? Ω Ω smaller resistance larger resistance Need Help? Read It THER = 660 Q. She then connects the same two resistors in parallel, and measuresRefer to the diagram below. V = 75.1 V; R1 = 83 Ohms; R2 = 116 Ohms; R3 = 73 Ohms; R4 = 123 Ohms; R5 = 111 Ohms; and R6 = 53 Ohms. How much power flows through resistor R6? 0.952 W 0.317 W 0.793 W 0.634 W
- A battery has an emf of 15.0 V. The terminal voltage of the battery is 10.6 V when it is delivering 22.0 W of power to an external load resistor R. (a) What is the value of R? Ω (b) What is the internal resistance of the battery? ΩThe circuit below contains two real batteries, each having significant internal resistance. Battery #1 has an EMF of 6.00 V and an internal resistance of 1.00 ohm. Battery #2 has an EMF of 12.00 V and an internal resistance of 2.00 ohms. These two batteries are connected in series with two resistors R, = 6.00 ohms and R,= 3.00 ohms. ri d (6.00,V) (1.00 0) R1 (6.00 N) R2 (3.00 N) a r2 E2 (2.00 Q) (12.00 V) 18. The current in the 12.00 Volt battery is equal to C. 0.500 A. A. 0.750 A. B. 1.00 A. D. 2.00 A. E. 1.50 A. 19. The potential difference across the terminals of battery #1 from point C to point d is equal to C. 7.00 V. A. 5.50 V. B. 6.00 V. D. 5.00 V. E. 6.50 V. 20. The potential difference across the terminals of battery #2 from point a to point b is equal to C. 13.00 V. A. 14.00 V. В. 10.00 V. D. 11.0 V. E. 12.00 V.