A baseball player's batting average is 0.341, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1-0.341 = 0.659. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits? What expression can be used to calculate the probability? O A. OB. (2) (3) (2) O C. 4 O D. 4 (0.341) (0.659)4 2 (0.341) (0.659)2 (0.341 +0.659)² (0.341 +0 (0.341)²(0.659)² The probability that the player had 2 hits in 4 at-bats is (Round to three decimal places as needed.)
A baseball player's batting average is 0.341, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1-0.341 = 0.659. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits? What expression can be used to calculate the probability? O A. OB. (2) (3) (2) O C. 4 O D. 4 (0.341) (0.659)4 2 (0.341) (0.659)2 (0.341 +0.659)² (0.341 +0 (0.341)²(0.659)² The probability that the player had 2 hits in 4 at-bats is (Round to three decimal places as needed.)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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