A baseball player's batting average is 0.341, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1-0.341 = 0.659. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits? What expression can be used to calculate the probability? O A. OB. (2) (3) (2) O C. 4 O D. 4 (0.341) (0.659)4 2 (0.341) (0.659)2 (0.341 +0.659)² (0.341 +0 (0.341)²(0.659)² The probability that the player had 2 hits in 4 at-bats is (Round to three decimal places as needed.)

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**Title: Calculating Probability of a Baseball Player's Hits Using Batting Average**

**Introduction:**
In baseball, a player's batting average (BA) is a key statistic that represents the likelihood of hitting the ball successfully during an at-bat. This concept can be applied to calculate the probability of specific outcomes in a series of at-bats.

**Problem Statement:**
A baseball player’s batting average is 0.341, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1 - 0.341 = 0.659. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits?

**Question:**
What expression can be used to calculate the probability?

**Options:**
A. 
\[
\left( \begin{array}{c}
6 \\
4 \\
\end{array} \right) (0.341)^{4} (0.659)^{4}
\]

B. 
\[
\left( \begin{array}{c}
4 \\
2 \\
\end{array} \right) (0.341)^4 (0.659)^{2}
\]

C. 
\[
\left( \begin{array}{c}
4 \\
2 \\
\end{array} \right) (0.341 + 0.659)^{2}
\]

D.
\[
\left( \begin{array}{c}
4 \\
2 \\
\end{array} \right) (0.341)^2 (0.659)^2
\]

**Answer Calculation Box:**
The probability that the player had 2 hits in 4 at-bats is \( \boxed{} \).
(Round to three decimal places as needed.)

**Explanation of Terms and Calculation:**
1. **Combination Calculation:** 
   \[
   \left( \begin{array}{c}
   n \\
   k \\
   \end{array} \right) 
   \]
   is the binomial coefficient, representing the number of ways to choose \( k \) successes (hits) out of \( n \) trials (at-bats).

2
Transcribed Image Text:**Title: Calculating Probability of a Baseball Player's Hits Using Batting Average** **Introduction:** In baseball, a player's batting average (BA) is a key statistic that represents the likelihood of hitting the ball successfully during an at-bat. This concept can be applied to calculate the probability of specific outcomes in a series of at-bats. **Problem Statement:** A baseball player’s batting average is 0.341, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1 - 0.341 = 0.659. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 2 hits? **Question:** What expression can be used to calculate the probability? **Options:** A. \[ \left( \begin{array}{c} 6 \\ 4 \\ \end{array} \right) (0.341)^{4} (0.659)^{4} \] B. \[ \left( \begin{array}{c} 4 \\ 2 \\ \end{array} \right) (0.341)^4 (0.659)^{2} \] C. \[ \left( \begin{array}{c} 4 \\ 2 \\ \end{array} \right) (0.341 + 0.659)^{2} \] D. \[ \left( \begin{array}{c} 4 \\ 2 \\ \end{array} \right) (0.341)^2 (0.659)^2 \] **Answer Calculation Box:** The probability that the player had 2 hits in 4 at-bats is \( \boxed{} \). (Round to three decimal places as needed.) **Explanation of Terms and Calculation:** 1. **Combination Calculation:** \[ \left( \begin{array}{c} n \\ k \\ \end{array} \right) \] is the binomial coefficient, representing the number of ways to choose \( k \) successes (hits) out of \( n \) trials (at-bats). 2
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