A base line was measured in four lengths giving 30.126, 29.973, 30.066, and 22.536 m. The differences of level were respectively 0.45, 0.60, 0.30, and 0.45 m. The temperature during observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 m, at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.000011 per °C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm, E=210×10³ N/mm², gravitational acceleration g=9.80665 m/s². a. Calculate the correct distance of the baseline. b. What tension should have been applied to eliminate the sag correction?
A base line was measured in four lengths giving 30.126, 29.973, 30.066, and 22.536 m. The differences of level were respectively 0.45, 0.60, 0.30, and 0.45 m. The temperature during observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 m, at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.000011 per °C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm, E=210×10³ N/mm², gravitational acceleration g=9.80665 m/s². a. Calculate the correct distance of the baseline. b. What tension should have been applied to eliminate the sag correction?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A base line was measured in four lengths giving 30.126, 29.973, 30.066, and 22.536 m. The
differences of level were respectively 0.45, 0.60, 0.30, and 0.45 m. The temperature during
observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 m,
at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.000011 per
°C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm, E=210×10³ N/mm²,
gravitational acceleration g=9.80665 m/s².
a. Calculate the correct distance of the baseline.
b. What tension should have been applied to eliminate the sag correction?
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