A barrel contains a 0.140-m layer of oil floating on water that is 0.255 m deep. The density of the oil is 610 kg/m³

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12.2

### Exercise 12.12

A barrel contains a 0.140-m layer of oil floating on water that is 0.255 m deep. The density of the oil is 610 kg/m³.

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#### Part A
**Question:**
What is the gauge pressure at the oil-water interface?

**Answer Input:**
```
P = ________ Pa
```
*Submit Answer Button*

---

#### Part B
**Question:**
What is the gauge pressure at the bottom of the barrel?

**Answer Input:**
```
P = ________ Pa
```
*Submit Answer Button*

---

### Explanation

To solve the problems, you need to understand the principle of fluid pressure. Gauge pressure at a certain depth is given by:

\[ P = \rho \cdot g \cdot h \]

Where:
- \(\rho\) is the density of the fluid (in kg/m³),
- \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\)),
- \(h\) is the height of the fluid column above the point in question (in meters).

In Part A, you are asked to find the gauge pressure at the oil-water interface. Specifically, you use the height and density of the oil.

In Part B, you need to find the gauge pressure at the bottom of the barrel. Here you would consider the cumulative height of both oil and water columns and their respective densities.
Transcribed Image Text:### Exercise 12.12 A barrel contains a 0.140-m layer of oil floating on water that is 0.255 m deep. The density of the oil is 610 kg/m³. --- #### Part A **Question:** What is the gauge pressure at the oil-water interface? **Answer Input:** ``` P = ________ Pa ``` *Submit Answer Button* --- #### Part B **Question:** What is the gauge pressure at the bottom of the barrel? **Answer Input:** ``` P = ________ Pa ``` *Submit Answer Button* --- ### Explanation To solve the problems, you need to understand the principle of fluid pressure. Gauge pressure at a certain depth is given by: \[ P = \rho \cdot g \cdot h \] Where: - \(\rho\) is the density of the fluid (in kg/m³), - \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\)), - \(h\) is the height of the fluid column above the point in question (in meters). In Part A, you are asked to find the gauge pressure at the oil-water interface. Specifically, you use the height and density of the oil. In Part B, you need to find the gauge pressure at the bottom of the barrel. Here you would consider the cumulative height of both oil and water columns and their respective densities.
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