A bar of square cross-section is subjected to point loads of P1, P2, P3, and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 130 kN, P2 = 230 kN & P4 = 180 kN. Also, determine the stresses in each section & the net change in the length of steel bar, where the respective side of a square and lengths are d1=55mm, L1=31 cm, d2 = 40mm, L2=38 cm, d3=55 mm & L3 =30 cm. Take E = 185 GPa. The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Stress in section 2 in N/mm2 is The Stress in section 3 in N/mm2 is and The total change in length in x10-3 mm is
A bar of square cross-section is subjected to point loads of P1, P2, P3, and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 130 kN, P2 = 230 kN & P4 = 180 kN. Also, determine the stresses in each section & the net change in the length of steel bar, where the respective side of a square and lengths are d1=55mm, L1=31 cm, d2 = 40mm, L2=38 cm, d3=55 mm & L3 =30 cm. Take E = 185 GPa. The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Stress in section 2 in N/mm2 is The Stress in section 3 in N/mm2 is and The total change in length in x10-3 mm is
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
A bar of square cross-section is subjected to point loads of P1, P2, P3, and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 130 kN, P2 = 230 kN & P4 = 180 kN. Also, determine the stresses in each section & the net change in the length of steel bar, where the respective side of a square and lengths are d1=55mm, L1=31 cm, d2 = 40mm, L2=38 cm, d3=55 mm & L3 =30 cm. Take E = 185 GPa.
The force P3 to make it to equilibrium in kN is
The Stress in section 1 in N/mm2 is
The Stress in section 2 in N/mm2 is
The Stress in section 3 in N/mm2 is and The total change in length in x10-3 mm is
Transcribed Image Text:dz
da
→P2
P3
di
P4
L3
L1
L2
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY