A bar of circular cross section is subjected to point loads of P1, P2, P3 and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 110 kN, P2 = 240 kN & P4 = 190 kN. Also, determine the stresses in each section & the net change in the length of steel bar. where d1=70mm, L1=33 cm, d2 = 30mm, L2=39 cm, d3=70 mm & L3 =34 cm. Take E = 174 GPa. - - --. d2 d1 P2 P3 + d3 P1 P4 L1 L2 L3 The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Compressive Stress in section 2 in N/mm² is

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Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.