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A bar of circular cross section is 2.5 m long. For 2 m of its length, its diameter is 200 mm while The bar is firmly supported at its ends and the remaining 0.5 m length, its diameter is 100 mm. subjected to a torque of 50 kN.m applied at its change of section. Shear modulus G = 8000 N/mm². T=50 kN•m -100mm ø B -200mm ø -2m 0.5m- Figure 1 a. Compute the shearing stress of the 200 mm bar section. b. Compute the shearing stress of the 100 mm bar section. c. Compute the angle of twist at the point of application of the torque.

A bar of circular cross section is 2.5 m long. For 2 m of its length, its diameter is 200 mm while The bar is firmly supported at its ends and the remaining 0.5 m length, its diameter is 100 mm. subjected to a torque of 50 kN.m applied at its change of section. Shear modulus G = 8000 N/mm². T=50 kN•m -100mm ø B -200mm ø -2m 0.5m- Figure 1 a. Compute the shearing stress of the 200 mm bar section. b. Compute the shearing stress of the 100 mm bar section. c. Compute the angle of twist at the point of application of the torque.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A bar of circular cross section is 2.5 m long. For 2 m of its length, its diameter is 200 mm while the remaining 0.5 m length, its diameter is 100 mm. The bar is firmly supported at its ends and subjected to a torque of 50 kN.m applied at its change of section. Shear modulus G = 8000 N/mm². T=50 kN•m -100mm ø B 0.5m -200mm ø -2m Figure 1 a. Compute the shearing stress of the 200 mm bar section. b. Compute the shearing stress of the 100 mm bar section. c. Compute the angle of twist at the point of application of the torque.
Transcribed Image Text:A bar of circular cross section is 2.5 m long. For 2 m of its length, its diameter is 200 mm while the remaining 0.5 m length, its diameter is 100 mm. The bar is firmly supported at its ends and subjected to a torque of 50 kN.m applied at its change of section. Shear modulus G = 8000 N/mm². T=50 kN•m -100mm ø B 0.5m -200mm ø -2m Figure 1 a. Compute the shearing stress of the 200 mm bar section. b. Compute the shearing stress of the 100 mm bar section. c. Compute the angle of twist at the point of application of the torque.
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