A bar of aluminum has a cross section of 1.0 cm × 1.0 cm and a length of 88 cm. What force F would be needed to stretch the bar to 1.0 m? 9.5 F = N Incorrect What is the tensile strain of the aluminum bar at that point? tensile strain: .14
A bar of aluminum has a cross section of 1.0 cm × 1.0 cm and a length of 88 cm. What force F would be needed to stretch the bar to 1.0 m? 9.5 F = N Incorrect What is the tensile strain of the aluminum bar at that point? tensile strain: .14
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Aluminum Bar Tensile Test**
A bar of aluminum has the following dimensions:
- Cross-sectional area: 1.0 cm × 1.0 cm
- Length: 88 cm
**Question 1:**
What force \( F \) would be needed to stretch the bar to a length of 1.0 m?
- Incorrect Attempt:
\[
F = 9.5 \, \text{N}
\]
**Question 2:**
What is the tensile strain of the aluminum bar at that point?
- Calculated tensile strain:
\[
\text{tensile strain} = 0.14
\]
The questions involve calculation of force required and the resulting tensile strain. The incorrect force value is highlighted, and the correct tensile strain is provided for further analysis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa46d264c-51d5-4389-b2be-e04c4259b1c7%2Fd823b202-7628-4746-b34c-62fb490d3d1f%2Fc97acz5_processed.png&w=3840&q=75)
Transcribed Image Text:**Aluminum Bar Tensile Test**
A bar of aluminum has the following dimensions:
- Cross-sectional area: 1.0 cm × 1.0 cm
- Length: 88 cm
**Question 1:**
What force \( F \) would be needed to stretch the bar to a length of 1.0 m?
- Incorrect Attempt:
\[
F = 9.5 \, \text{N}
\]
**Question 2:**
What is the tensile strain of the aluminum bar at that point?
- Calculated tensile strain:
\[
\text{tensile strain} = 0.14
\]
The questions involve calculation of force required and the resulting tensile strain. The incorrect force value is highlighted, and the correct tensile strain is provided for further analysis.
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