A bank has a policy that the proportion of loans made to people with more than $50,000 in debt should no be more than 0.15. The bank checks a randomly chosen sample of 75 customer's debt amounts to determine if the proportion is more than 0.15 at a significance level of 0.05. Use Sheet 2 of the Excel file, which gives the customer's debt amounts for the 75 people in the sample, to calculate p, the z-score, and the p-value. p = Ex: 1.234 z = n=
A bank has a policy that the proportion of loans made to people with more than $50,000 in debt should no be more than 0.15. The bank checks a randomly chosen sample of 75 customer's debt amounts to determine if the proportion is more than 0.15 at a significance level of 0.05. Use Sheet 2 of the Excel file, which gives the customer's debt amounts for the 75 people in the sample, to calculate p, the z-score, and the p-value. p = Ex: 1.234 z = n=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Spreadsheet 2
![A bank has a policy that the proportion of loans made to people with more than $50,000 in debt should not be more than 0.15. The bank checks a randomly chosen sample of 75 customer's debt amounts to determine if the proportion is more than 0.15 at a significance level of 0.05.
Use Sheet 2 of the Excel file, which gives the customer's debt amounts for the 75 people in the sample, to calculate \( \hat{p} \), the \( z \)-score, and the \( p \)-value.
\[
\hat{p} = \text{Ex: 1.234}
\]
\[
z =
\]
\[
p =
\]
Since the \( p \)-value is [Pick] than the significance level 0.05, the null hypothesis [Pick].
[Pick] evidence exists that the proportion of loans to people with more than $50,000 in debt is more than 0.15.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafa77d54-ffb2-4772-a246-c955b3ec6a36%2Fe8c3a75c-c2a6-49e8-b5a2-25651cdbc4dd%2Fe9hqx2h_processed.png&w=3840&q=75)
Transcribed Image Text:A bank has a policy that the proportion of loans made to people with more than $50,000 in debt should not be more than 0.15. The bank checks a randomly chosen sample of 75 customer's debt amounts to determine if the proportion is more than 0.15 at a significance level of 0.05.
Use Sheet 2 of the Excel file, which gives the customer's debt amounts for the 75 people in the sample, to calculate \( \hat{p} \), the \( z \)-score, and the \( p \)-value.
\[
\hat{p} = \text{Ex: 1.234}
\]
\[
z =
\]
\[
p =
\]
Since the \( p \)-value is [Pick] than the significance level 0.05, the null hypothesis [Pick].
[Pick] evidence exists that the proportion of loans to people with more than $50,000 in debt is more than 0.15.
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