A bank examiner's record shows that the probability of an error in a statement fo a checking account at Trust Us Bank is 0.03. The bank statements are sent monthly. What is the probability that exactly two of the next 12 monthly statements for our account will be in error? Now use the cumulative probability option to find the probability that at most two of the next 12 statements contain errors. Use this result with subtraction to find the probability that more than two of the next 12 statements contain errors.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
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Question 2
A bank examiner's record shows that the probability of an error in a statement for
a checking account at Trust Us Bank is 0.03. The bank statements are sent
monthly. What is the probability that exactly two of the next 12 monthly
statements for our account will be in error? Now use the cumulative probability
option to find the probability that at most two of the next 12 statements contain
errors. Use this result with subtraction to find the probability that more than two
of the next 12 statements contain errors.
Your Answer:
X-B(0.03,12)
P(x-12)
P(x-12)3D0
P(error)= P3D0.03
n=12
X= no statement of error
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4
Transcribed Image Text:Question 2 A bank examiner's record shows that the probability of an error in a statement for a checking account at Trust Us Bank is 0.03. The bank statements are sent monthly. What is the probability that exactly two of the next 12 monthly statements for our account will be in error? Now use the cumulative probability option to find the probability that at most two of the next 12 statements contain errors. Use this result with subtraction to find the probability that more than two of the next 12 statements contain errors. Your Answer: X-B(0.03,12) P(x-12) P(x-12)3D0 P(error)= P3D0.03 n=12 X= no statement of error Search or type URL 4
2/4 pts
Question 3
Some tables for the binomial distribution give values only up to 0.5 for the
probability of success p. There is symmetry to the values for p greater than 0.5
with those values of p less than 0.5.
• Consider the binomial distribution withn= 10 and p = .75. Since there are 0-
10 successes possible, put 0 - 10 in L1. Use probability option (binompdf)
with L1 and store the distribution probabilities in L2.
• Now consider the binomial distribution with n = 10 and p = .25. Use
probability option (binompdf) with L1 and store the distribution probabilities
in L3.
• Now make a table that displays L1, L2,and L3 and see if you can discover the
symmetries of L2 with L3. For example, how does P(K = 4 successes with p =
.75) compare to P(K = 6 successes with p = .25)?
Your Answer:
X-B(10, .75)
P(x-.75)
P(x- .75)= 1
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Transcribed Image Text:2/4 pts Question 3 Some tables for the binomial distribution give values only up to 0.5 for the probability of success p. There is symmetry to the values for p greater than 0.5 with those values of p less than 0.5. • Consider the binomial distribution withn= 10 and p = .75. Since there are 0- 10 successes possible, put 0 - 10 in L1. Use probability option (binompdf) with L1 and store the distribution probabilities in L2. • Now consider the binomial distribution with n = 10 and p = .25. Use probability option (binompdf) with L1 and store the distribution probabilities in L3. • Now make a table that displays L1, L2,and L3 and see if you can discover the symmetries of L2 with L3. For example, how does P(K = 4 successes with p = .75) compare to P(K = 6 successes with p = .25)? Your Answer: X-B(10, .75) P(x-.75) P(x- .75)= 1 Search or type URL
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