A balloon filled with helium has a volume of 38.4 L at 279 K. What volume will the balloon occupy at 247 K? V = L

Chemistry
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Chapter1: Chemical Foundations
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A balloon filled with helium has a volume of 38.4 L at 279 K. What volume will the balloon occupy at 247 K?

\[ V = \text{______} \, \text{L} \]

---

**Explanation of the Context:**

This problem involves using Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin), assuming the pressure and the amount of gas remain constant. The law is mathematically expressed as:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

- \( V_1 \) is the initial volume.
- \( T_1 \) is the initial temperature.
- \( V_2 \) is the final volume.
- \( T_2 \) is the final temperature.

In this scenario:
- \( V_1 = 38.4 \, \text{L} \)
- \( T_1 = 279 \, \text{K} \)
- \( T_2 = 247 \, \text{K} \)

You are asked to find \( V_2 \), the new volume of the balloon at 247 K.
Transcribed Image Text:A balloon filled with helium has a volume of 38.4 L at 279 K. What volume will the balloon occupy at 247 K? \[ V = \text{______} \, \text{L} \] --- **Explanation of the Context:** This problem involves using Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin), assuming the pressure and the amount of gas remain constant. The law is mathematically expressed as: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] - \( V_1 \) is the initial volume. - \( T_1 \) is the initial temperature. - \( V_2 \) is the final volume. - \( T_2 \) is the final temperature. In this scenario: - \( V_1 = 38.4 \, \text{L} \) - \( T_1 = 279 \, \text{K} \) - \( T_2 = 247 \, \text{K} \) You are asked to find \( V_2 \), the new volume of the balloon at 247 K.
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