A ball rolls off the edge of a tabletop 1 m above the floor with horizontal velocity of 1 m/s. Find: Time it takes to hit the floor The horizontal distance it coversThe velocity when it hits the floor

We'll use the freefall formula, rearranged to give us time. When it comes to the vertical dimension, the ball is acting just like a dropped ball. Nature doesn't care that it's also moving forward at the same time. So the equation is given by, d=12gt2t=2dgd: Heightg: acceleration due to gravityWe know that, t=2dgd=1mg=9.8ms-1t=2×1m9.8ms-1=0.45s It will take 0.45s to hit the ball.For horizontal distance covered we can use the basic distance formula, d=s×ts=1ms-1t=0.45sd=1ms-1×0.45s=0.45m The ball will move 0.45mWe know that , v=v0+gtv0=1ms-1g=9.8ms-1t=0.45sv=1ms-1+9.8ms-1×0.45s=5.41ms-1The velocity of ball when it hits the ground is 5.41ms-1

Answered: A ball rolls off the edge of a tabletop…

A ball rolls off the edge of a tabletop 1 m above the floor with horizontal velocity of 1 m/s. Find: Time it takes to hit the floor The horizontal distance it covers The velocity when it hits the floor